<em><u>Question:</u></em>
Consider the following equation: f(x)=x^2+4\4x^2-4x-8 name the vertical asymptote(s)
<em><u>Answer:</u></em>
The vertical asymptotes are x = 2 or x = -1
<em><u>Solution:</u></em>
Given that,
For vertical asymptotes, set the denominator to zero and then solve the quadratic equation
Thus the vertical asymptotes are x = - 1 and x = 2
Answer:
Step-by-step explanation:
I am joyous to assist you at any time.
Is that the whole question? It does not specify, so that means there is a 50/50 chance for either.
Answer: 150 boys
Step-by-step explanation:
Let the number of boys be x
Since there were 200 more girls than boys, the number of girls will be: = x + 200
Since the ratio of boys to girls was 3:7, this can be solved further below:
3/7 = x/x+200
Cross multiply
(7 × x) = 3(x + 200)
7x = 3x + 600
7x - 3x = 600
4x = 600
x = 600/4
x = 150
The number of boys enrolled is 150
Number of Girls will be:
= X + 200
= 150 + 200
= 350
Check: Number of boys / Number of girls
= 150/350
= 3/7
= 3:7
Answer:
The sum of x and y is 8.
Step-by-step explanation:
x+2y=10
x-2y=2
------------
2x = 12, so x = 6. Substituting 6 for x in the 2nd equation, we get:
6 - 2y = 2, or
4 = 2y, or y = 2. The solution is therefore (6, 2).
The sum of x and y is 6 + 2 = 8 (answer)
