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3 years ago

Jordan is three years older than four times Lily's age. The sum of their age is 68. How old is Jordan?

Mathematics

1 answer:

almond37 [142]3 years ago

5 0

You have to multiply 4times 3 with gives you 12 plus 68

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Help please! <3

lora16 [44]

-x/2 + 4 > = 6
-x/2 > = 6 - 4
-x/2 > = 2...multiply both sides by -2
x < = -4
_________________________________________
x + 3/2 < 7/4
x < 7/4 - 3/2
x < 7/4 - 6/4
x < 1/4

6 0

2 years ago

Plane tickets to Chicago usually cost $120. On a travel deal website, you scored a coupon for 35% off. Your budget for the trip

enot [183]

Answer: yes it’s 78$

Step-by-step explanation: The difference is 42.00

4 0

2 years ago

In its monthly report, the local animal shelter states that it currently has 24 dogs and 18 cats available for adoption. Eight o

andrezito [222]

Answer with Step-by-step explanation:

We are given that

Total dogs=24

Total cats=18

Total animals=24+18=42

Male dogs=8

Male cats=6

Total male animals=8+6=14

Total female animals=42-14=28

Female cats=18-6=12

Dogs female=24-8=16

a.We have to find the probability that the pet is male, given that it is cat.

It means we have to find P(Male/cat)

Conditional probability: $P(A/B)=\frac{P(A\cap B)}{P(B)}$

P(Cat)= $\frac{18}{42}$

$P(male cat)=\frac{6}{42}$

$P(Male/cat)=\frac{\frac{6}{42}}{\frac{18}{42}}$

P(male/cat)= $\frac{6}{18}=0.33$

b. $P(female cat)=\frac{12}{42}$

$P(female)=\frac{28}{42}$

$P(Cat/Female)=\frac{\frac{12}{42}}{\frac{28}{42}}=\frac{12}{28}=0.43$

c.P(Dog)= $\frac{24}{42}$

$P(dog female)=\frac{16}{42}$

$P(female/dog)=\frac{\frac{16}{42}}{\frac{24}{42}}$

$P(female/dog)=\frac{16}{24}=0.67$

5 0

3 years ago

Remember to show work and explain. Use the math font.

vichka [17]

Answer:

$\large\boxed{1.\ f^{-1}(x)=\sqrt[12]{3^x}}\\\\\boxed{2.\ f^{-1}(x)=\sqrt[4]{3^x}}\\\\\ \boxed{3.\ f^{-1}(x)=\sqrt[3]{4^{7-x}}}$

Step-by-step explanation:

$(a^n)^m=a^{nm}\\\\\log_ab=c\iff a^c=b\\\\a^{\log_ax}=x\\\\n\log_ab=\log_ab^n\\\\\log_ab+\log_ac=\log_a(bc)\\============================\\\\1.\\y=3\log_3x^4\to y=\log_3(x^4)^3\to y=\log_3x^{12}$

$2.\\y=\log_3x^4\\\\\text{Exchange x and y. Solve for y:}\\\\\log_3y^4=x\Rightarrow3^{\log_3y^4}=3^x\Rightarrow y^{4}=3^x\\\\y=\sqrt[4]{3^x}\\-------------------------$

$3.\\y=-\log_4x^3+7\\\\\text{Exchange x and y. Solve for y:}\\\\-\log_4y^3+7=x\qquad\text{subtract 7 from both sides}\\\\-\log_4 y^3=x-7\qquad\text{change the signs}\\\\\log_4y^3=7-x\Rightarrow4^{\log_4y^3}=4^{7-x}\\\\y^3=4^{7-x}\Rightarrow y=\sqrt[3]{4^{7-x}}$

7 0

2 years ago

Angle ABC has point E on ray BA and point D on ray BC. Points E and D are equidistant from point B. To bisect angle ABC, which o

aivan3 [116]

Answer:

The point in the angle that is equidistant from points E and D

Step-by-step explanation:

I took all three quizzes show me if you have any other questions

3 0

2 years ago