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3 years ago

What is 35 divided by 150

Mathematics

1 answer:

Kaylis [27]3 years ago

4 0

Answer: 0.2333333.....

Step-by-step explanation:

35/150 im simplest form is 7/30

and 7/30 is equal to 0.23 repeated

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PLEASE HELP ASAP!!!

Mila [183]

Answer:

4. x=0 x=5

5. x=-4 x=8

6 0

3 years ago

A unit fraction is a fraction with a numerator of 1. What is the greatest unit fraction that you can plot on a number line betwe

Pie

That should be 1/1 because if you do 4/1 or 2/1, that would be greater than 1. Also, since you can't do anything with the numerator above 1, 1/1 would be the greatest unit fraction between 0 and 1

6 0

3 years ago

An investment of $8,000 earns interest at an annual rate of 7% compounded continuously. Complete parts (A) and (B) below. Click

Sergeeva-Olga [200]

Answer:

A. $\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

B. $\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

Step-by-step explanation:

Given that:

An investment of Amount = $8000

earns at an annual rate of interest = 7% = 0.07 compounded continuously

The objective is to :

A) Find the instantaneous rate of change of the amount in the account after 2 year(s).

we all know that:

$A = Pe^{rt}$

where;

$A = (8000) \ e ^{0.7t}$

The instantaneous rate of change = $\dfrac{dA}{dt}$

$\dfrac{dA}{dt} = \dfrac{d}{dt}(8000 \ e ^{0.07t} )$

$= 8000 \dfrac{d}{dt}e^{0.07 \ t}$

$\dfrac{dA}{dt}= 8000 (0.07)e^{0.07 \ t}$

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 2 years; the instantaneous rate of change is:

$\dfrac{dA}{dt}|_{t=2}= 560 e^{0.07 \times 2}$

$\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

(B) Find the instantaneous rate of change of the amount in the account at the time the amount is equal to $12,000.

Here the amount = 12000

$12000 = (8000)e^{0.07 \ t}$

$\dfrac{12000 }{8000}= e^{0.07 \ t}$

$1.5= e^{0.07 \ t}$

㏑(1.5) = 0.07 t

0.405465 = 0.07 t

t = 0.405465 /0.07

t = 5.79

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 5.79

$\dfrac{dA}{dt}|_{t = 5.79}= 560 e^{0.07 \times 5.79}$

$\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

7 0

3 years ago

The level of water in a dam was decreasing by 20% each day. If the level of water was 1500cm,what was the level after two days?

makkiz [27]

Answer:

$L_o= 1500 cm$

And we know that the level is decreasing 20% each day so then we can use the following model for the problem

$L_f = L_o (1-0.2)^t$

Where t represent the number of days and L the level for this case we want to fnd the level after two days so then t =2 and replacing we got:

$L_f = 1500cm(0.8)^2 = 960cm$

Step-by-step explanation:

For this case we know that the initial volume of water is:

$L_o= 1500 cm$

And we know that the level is decreasing 20% each day so then we can use the following model for the problem

$L_f = L_o (1-0.2)^t$

Where t represent the number of days and L the level for this case we want to fnd the level after two days so then t =2 and replacing we got:

$L_f = 1500cm(0.8)^2 = 960cm$

6 0

4 years ago

A full glass of water can hold 1/6 of a bottle.

uysha [10]

Answer:

21 glasses of water.

Step-by-step explanation:

You can do a proportion.

$\fraction{1 glass}{1/6 of a bottle)$ or

1 glass/1/6 of a bottle.

x glasses/3.5 bottles.

You can cross multiply.

1/6 times x is 1/6x

1 times 3.5 is 3.5/

1/6x=3.5.

do the reciprocal of 1/6 which is 6.

So, 6 times 3.5 is 21.

Therefore, you have 21 glasses of water.

4 0

4 years ago