Answer:
The correct option is (c).
Step-by-step explanation:
The complete question is:
The data for the student enrollment at a college in Southern California is:
Traditional Accelerated Total
Math-pathway Math-pathway
Female 1244 116 1360
Male 1054 54 1108
Total 2298 170 2468
We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?
a. 1360/2468 and 116/170
b. 170/2468 and 116/1360
c. 1360/2468 and 170/2468
Solution:
If two events <em>A</em> and <em>B</em> are independent then:

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.
Consider the following probabilities:

If the two events are independent then:
P (F|A) = P(F)
&
P (A|F) = P (A)
But what would not be a valid comparison is:
P (A) = P(F)
Thus, the correct option is (c).
Use the formula y2-y1/x2-x1.
3-3/-4-8
0/-12
The slope is 0, so the line is horizontal.
<span>Least Common Denominator (LCD) is the least number which all the denominators can divide without remainder. The given denominators are 2, 16 and 8. The least number 2, 16 and 8 will divide without remainder is 16. Therefore, to express the fractions 1/2, 3/12, and 7/8 with an LCD, we multiply both the numerator and the denominator of each of the fractions with a common factor that makes the denominator to be 16. Therefore, 1/2, 3/16 and 7/8 expressed with an LCD are (1 x 8) / (2 x 8), 3/16, (7 x 2) / (8 x 2) = 8/16, 3/16, and 14/16.</span>
Answer:
D. 216 cubic centimetres.
Step-by-step explanation:
The answer is D, because 6 to the 3rd power is 216. therefore, if the side length is 6, the answer is 216.
Ok so the only ones that we know for sure are 4 = 1, 6=8, 7=9 and you can’t really do all that much with 2,3,5 because it’s not as obvious