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Setler79 [48]
3 years ago
9

A chef draws cookies randomly from a box containing 6 cookies of the same shape and size. There is 1 chocolate cookie, 3 almond

cookies, and 2 butter cookies. He draws 1 cookie and then draws another cookie without replacing the first one. Find the probability of picking 1 almond cookie followed by another almond cookie, and show the equation used.
Mathematics
1 answer:
Anon25 [30]3 years ago
8 0
First there was a 3/6 or 50% chance of getting an almond cookie. (3 out of 6 cookies are almond) then, it became a 2/5 or 40% chance of getting an almond cookie. (2 out of 5 cookies are almond) multiple 3/6 by 2/5 and you get 6/30 which can be simplified to 1/5.
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Please please help me please help please please help me please help please
AVprozaik [17]

Answer:

Perimeter is 17.07

Step-by-step explanation:

We know that DF = EF = 5 cm, since D and E are the midpoints of AC and AB, both of which are 10 cm in length.

We need to use the Pythagorean theorem to get the length of DE.

DE = \sqrt{5^{2} +5^{2}}=\sqrt{50}  = 7.07\\

So the perimeter of DEF is 5 + 5 + 7.07 = 17.07

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3 years ago
The answer for 6y-1=5
olya-2409 [2.1K]
The answer to this is Y = 1
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3 years ago
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Which of the following is a defined term?<br> Angle<br> Line<br> Point<br> Plane
Anna11 [10]

Answer:

C. Point is a defined term

Step-by-step explanation:

kleann

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2 years ago
Find a ratio equivalent to 15/60
Flauer [41]

Answer:

\large\boxed{\dfrac{15}{60}=\dfrac{5}{20}=\dfrac{3}{12}=\dfrac{1}{4}}

or

\large\boxed{\dfrac{15}{60}=\dfrac{30}{120}=\dfrac{45}{180}=\dfrac{60}{240}}

Step-by-step explanation:

Divide the numerator and the denominator by the same number:

\dfrac{15}{60}\\\\=\dfrac{15:5}{60:5}=\dfrac{3}{12}\\\\=\dfrac{15:3}{60:3}=\dfrac{5}{20}\\\\=\dfrac{15:15}{60:15}=\dfrac{1}{4}\\\vdots

or

Multiply the numerator and the denominator by the same number:

\dfrac{15}{60}\\\\=\dfrac{15\cdot2}{60\cdot2}=\dfrac{30}{120}\\\\=\dfrac{15\cdot3}{60\cdot3}=\dfrac{45}{180}\\\\=\dfrac{15\cdot4}{60\cdot4}=\dfrac{60}{240}\\\vdots

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First,

We are dealing with parabola since the equation has a form of,

y=ax^2+bx+c

Here the vertex of an up - down facing parabola has a form of,

x_v=-\dfrac{b}{2a}

The parameters we have are,

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Plug them in vertex formula,

x_v=-\dfrac{-10}{2(-5)}=-1

Plug in the x_v into the equation,

y_v=-5(-1)^2-10(-1)+6=11

We now got a point parabola vertex with coordinates,

(x_v, y_v)\Longrightarrow(-1,11)

From here we emerge two rules:

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So our vertex is minimum value since,

a=-5\Longleftrightarrow a

Hope this helps.

r3t40

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3 years ago
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