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Svetlanka [38]
3 years ago
8

20 points thank you to who ever

Mathematics
1 answer:
Travka [436]3 years ago
4 0

Answer:

uh

Step-by-step explanation:

couldnt figure out how to leave XD

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|x| + 6 = 3 <br><br> A question on homework
alexdok [17]

Answer:

-9

Step-by-step explanation:

-9+6=-3

5 0
3 years ago
A geologist in South America discovers a bird skeleton that contains 80% of its original amount of C-14. N0= initial amont of C-
kap26 [50]

A geologist in South America discovers a bird skeleton that contains 80% of its original amount of C-14

We use formula N = N_oe^{-kt}

N0= initial amont of C-14 (at time t=0)

N= amount of C-14 at time t

t= time, in years

k= 0.0001

N is 80% of N0 that is N= 0.80N_o

N = N_oe^{-kt}

0.80N_o = N_oe^{-kt}

Divide both sides by N_o

0.8=e^{-0.0001 t}

Take ln on both sides

ln(0.8)=lne^{-0.0001 t}

ln(0.8) = -0.0001t ln(e)

ln(0.8) = -0.0001t

Divide both sides by -0.001

t = 2231.435513

The age of the bird skeleton is 2231 years old




5 0
3 years ago
Happy Paws charges $17.00 plus $5.50 per hour to keep a dog during the day. Woof Watchers charges
mafiozo [28]

Answer:

4.80

Step-by-step explanation:

17+5.50h=11+6.75h

- subtract 11 from both sides

-subtract 5.50 from both sides

-divide to get h alone

8 0
3 years ago
1/3 cube root 27 &lt;=w
Rainbow [258]

3³ = 27

∛27 = 3

1/3 of 3 = 1

x\geq1

5 0
4 years ago
Read 2 more answers
Which equation represents a slope of −4 and y-intercept of (0,2)?
blsea [12.9K]

Answer:

y=-4x+2

Step-by-step explanation:

Hi there!

We want to find out which equation represents a line with a slope of -4 and a y intercept of (0,2)

The most common way to write the equation of the line is in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept

We have everything we need to plug into the equation, let's just label the values to avoid confusion

m=-4

b=2 (when you substitute the y intercept as b, b is the value of y in the point)

Now substitute into the equation

y=-4x+2

Hope this helps!

6 0
3 years ago
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