The answer oils be 2 square root 2 because 4 times 2 is 8 and because the square root of 4 is 2 you would move that 2 to the outside and keep the other two on the inside of the square root.
Answer:
Step-by-step explanation:
The volume of a rectanguiar shape like this one is V = L * W * H, where the letters represent Length, Width and Height. Here L is the longest dimension and is 28 - 2x; W is the width and is 22-2x; and finally, x is the height. Thus, the volume of this box must be
V(x) = (28 - 2x)*(22 - 2x)*x
and we want to maximize V(x).
One way of doing that is to graph V(x) and look for any local maximum of the graph. We'd want to determine the value of x for which V(x) is a maximum.
Another way, for those who know some calculus, is to use the first and second derivatives to identify the value of x at which V is at a maximum.
I have provided the function that you requested. If you'd like for us to go all the way to a solution, please repost your question.
Let log5 125 = x
Removing log you get 5^x = 125
Rewrite 125 as 5^3
Now 5^x = 5^3
x = 3
Area = b*h and in some cases * 2 so you need to do this, 64*52 + 40*28= 4448 yd2
Answer:
15 B
16 C
17 A
Step-by-step explanation:
