Answer:
37005
36740
35205
Step-by-step explanation:
Upon a slight rearrangement this problem gets a lot simpler to see.
x^3-x+2x^2-2=0 now factor 1st and 2nd pair of terms...
x(x^2-1)+2(x^2-1)=0
(x+2)(x^2-1)=0 now the second factor is a "difference of square" of the form:
(a^2-b^2) which always factors to (a+b)(a-b), in this case:
(x+2)(x+1)(x-1)=0
So g(x) has three real zero when x={-2, -1, 1}
Answer:
x = 5m/s
Step-by-step explanation:
Distance flying out = 12 km (headwind)
Distance flying back = 12 km (tailwind)
total distance = 12 + 12 =24 km
wind speed = 1km/h
speed going out (with headwind) = (x - 1) km/h
speed coming back (with tailwind) = (x + 1) km/h
Time taken to go out = distance going out / speed going out
= 12 / (x-1)
Time taken to come back = distance coming back / speed coming back
= 12 / (x+1)
total time = time taken to go out + time taken to come back
5 =[ 12/(x-1) ] + [ 12/(x-1)]
expanding this, we will get
5x² - 24x - 5 = 0
solving quadratic equation, we will get
x = -1/5 (impossible because speed cannot be negative)
or
x = 5 (answer)
Answer: Whoever read the 15 pages before read the most.
Step-by-step explanation:
Answer:
x = -2 and y = 2
Step-by-step explanation:
We have the following system of linear equations;
y=x+4
y=-2x-2
To solve the above system, we shall be equating the right hand sides of the two equations since we have y's on the left hand side of both equations;
x + 4 = -2x - 2
add 2x on both sides of the equation;
x + 4 + 2x = -2x - 2 + 2x
3x + 4 = -2
subtract 4 on both sides of the equation;
3x + 4 - 4 = -2 - 4
3x = -6
x = -2
We can use the first equation y=x+4 to determine the value of y;
y = -2 + 4
y = 2
The solution to the system of linear equations is thus;
x = -2 and y = 2
