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Luden [163]
3 years ago
14

The system of linear equations 5x+2y = 3 and x+y = -1 is graphed below.What is the solution to the system of equations?

Mathematics
1 answer:
Kazeer [188]3 years ago
7 0

Answer:

<h2>C. (3, -4)</h2>

Step-by-step explanation:

If the system of linear equations is graphed, then the solution is the intersection of lines.

Read it from the graph (look at the picture).

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Help plz fast with this question
Ivahew [28]

90-7 =83 degrees

height = 3 miles

divide 3 by the cos of 83 degrees

3/cos(83) = 24.6165

rounded to nearest mile = 25 miles

6 0
3 years ago
Halp me plz.........................................
KengaRu [80]

The second one. 4/6 and 2/3

4 0
3 years ago
The sequence a1 = 6, an = 3an-1 can also be written as
wariber [46]
The question as presented is incomplete, here is the complete question with the multiple choice:

The sequence a1 = 6, an = 3an − 1 can also be written as:

1) an = 6 ⋅ 3^n
2) an = 6 ⋅ 3^(n + 1) 
3) an = 2 ⋅ 3^n
4) an = 2 ⋅ 3^(n + 1)

The correct choice is option 3) an = 2⋅3^n.

If we look at the initial sequence an = 3⋅an-1, and

a1 = 3⋅a0 = 6
a0 = 6/3
a0 = 2

We can now look at the sequence.

a0 = 2
a1 = 6
a2 = 18
a3 = 54
etc...

A common factor in each of those numbers is 2, so we can rewrite the sequence by factoring out 2.

a0 = 2⋅1
a1 = 2⋅3
a2 = 2⋅9
a3 = 2⋅27

The numbers being multiplied by 2 are all factors of 3. So we can rewrite the sequence again as:

a0 = 2⋅3^0
a1 = 2⋅3^1
a2 = 2⋅3^2
a3 = 2⋅3^3

This sequence can now be rewritten as an = 2⋅3^n.
7 0
3 years ago
For which interval does this quadratic inequality hold true?
adoni [48]

Answer:

D

Step-by-step explanation:

x²-4x-12≤0

x²-6x+2x-12≤0

x(x-6)+2(x-6)≤0

(x-6)(x+2)≤0

x=6,-2

∴ value of x lies between -2 & 6

3 0
11 months ago
A 30 gram sample of a substance that's used to sterilize surgical instruments has a k-value of 0.1235. Find the substances half
jok3333 [9.3K]

Answer : The substances half life in days is, 5.6 days.

Step-by-step explanation :

Half life : It is defined as the amount of time taken by a radioactive material to decay to half of its original value.

All radioactive decays follow first order kinetics.

The relation between the half-life and rate constant is:

k=\frac{0.693}{t_{1/2}}

where,

k = rate constant = 0.1235 per days

t_{1/2} = half-life

Now put all the given values in the above formula, we get:

0.1235\text {days}^{-1}=\frac{0.693}{t_{1/2}}

t_{1/2}=5.6\text{ days}

Thus, the substances half life in days is, 5.6 days.

5 0
3 years ago
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