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3 years ago

I am so bored yall ttm plz

Mathematics

2 answers:

mafiozo [28]3 years ago

7 1

Same

Explanation : same

Akimi4 [234]3 years ago

4 1

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Angles of XYZ and ABC are the blank because the triangle are blank and corresponding angles are blank.

Jobisdone [24]

Answer:

the answer is your teacher just wanted to draw a triangle and get paid for it.

4 0

2 years ago

What sum of money amounts to rupees 8700 in 3 years at the rate of 24 % per annum

Zina [86]

Given:

Amount = 8700

Time = 3 years

Rate of interest = 24% per annum

To find:

The principal values.

Solution:

Formula for amount:

$A=P\left(1+\dfrac{r}{100}\right)^t$

Where, A is amount, P is principal, r is the rate of interest and t is the number of years.

Putting $A=8700,r=24,t=3$ , we get

$8700=P\left(1+\dfrac{24}{100}\right)^{3}$

$8700=P\left(1+0.24\right)^{3}$

$8700=P\left(1.24\right)^{3}$

$8700=1.906624P$

Divide both sides by 1.906624.

$\dfrac{8700}{1.906624}=P$

$4563.0391729=P$

$P\approx 4563.04$

Therefore, the principal value is about 4563.04.

8 0

2 years ago

Explain how multiplying with 6 is like multiplying with 3

marusya05 [52]

They are alike because you are just doubling the number by 2

3 0

3 years ago

Read 2 more answers

You made two deposits to your bank accounts this month. One deposit was $17.92, and the second deposit was $15.33. Your balance

WITCHER [35]

$72.31 is the total amount AFTER ADDING TWO DEPOSITS

So, if we want to know the amount before deposits, we just need to take the total of previous two deposits

The expressions that show your balance would be

$72.31 – $17.92 – $15.33; $39.06

6 0

2 years ago

Show with work please.

kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that $\text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$