What is the value of x ??
2 answers:
You might be interested in
Answer:
The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
Step-by-step explanation:
We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
The idea being, we first, move the repeating part to the left of the decimal point, by simply multiplying it by a power of 10, in this case, we need to move 318, so we need then 1000, 3 decimals, 3 zeros.
and we'll make the expression a variable, so let's do so first,
and we'll make the expression a variable, so let's do so first,
Given:
Point = (8, 4)
To find:
The slope-intercept form of the equation of the line.
Solution:
Slope of this line = .
Slope of the line is same as the slope of .
Slope of the line (m) =
General form of line:
y = mx + b
---------- (1)
It contains the point (8, 4). Substitute x = 8 and y = 4 in (1).
Subtract 4 from both sides, we get
b = 0
Substitute b = 0 in (1).
Equation of the line:
<u>Complete the sentence:</u>
; I used the general form of a line in slope-intercept form, y = mx + b. The slope, m is
. Then I substituted 8 for x and 4 for y into the standard form and solved for b, which is 0.