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Umnica [9.8K]
3 years ago
13

Amanda and Ndiba are selling flower bulbs for a school fundraiser. Customers can buy packages of tulip bulbs and bags of daffodi

l bulbs. Amanda sold 6 packages of tulip bulbs and 12 bags of daffodil bulbs for a total of $198. Ndiba sold 7 packages of tulip bulbs and 6 bags of daffodil bulbs for a total of $127. Find the cost each of one package of tulips bulbs and one bag of daffodil bulbs.
Please answer with work, need this quick! thanks
Mathematics
1 answer:
Gemiola [76]3 years ago
5 0

Answer is on the attachment. Brainlist pls.

Step-by-step explanation:

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Factor the polynomial.
MArishka [77]
2x^4 + 4x^3 + 6x^2 = 2x^2(x^2 + 2x + 3)
5 0
4 years ago
Read 2 more answers
Find the slope of the slope through the points (-4 , -4) and (2,5)
Colt1911 [192]

Answer:

3/2

Step-by-step explanation:

In order to find the slope with two points, you use this formula:

y2-y1 / x2 - x1.

y2 is 5 and y1 is -4. 5 - -4 = 9

x2 is 2 and x1 is -4. 2 - - 4 = 6

9/6 = 3/2.

5 0
3 years ago
Solve for k.
EastWind [94]
To do this we need to rearrange the equation.
m = -8j - 9k + 9
Subtract (-8j + 9) from both sides
m + 8j - 9 = -9k
Divide both sides by -9
(m + 8j - 9)/-9 = k

The answer is C
6 0
3 years ago
Please help!!!!! ASAP!!!
nika2105 [10]
That's just the distance between 2 points
the distance between (x1,y1) and (x2,y2) is
D= \sqrt{(x2-x1)^2+(y2-y1)^2}

we can find the distance between S and Q or P and R

S and Q is (0,0) and (a,b)

D= \sqrt{(a-0)^2+(b-0)^2}
D= \sqrt{a^2+b^2}

distance between P and R is between(0,b) and (a,0)
D= \sqrt{(a-0)^2+(0-b)^2}
D= \sqrt{(a)^2+(-b)^2}
D= \sqrt{a^2+b^2}

\sqrt{a^2+b^2} = \sqrt{a^2+b^2}
so the lengths of diagonals are congruent
7 0
4 years ago
David started across a lake 15 miles wide in his fishing boat at 10 miles per hour. He had to row the rest of the way at only 5
schepotkina [342]

Answer:

Total time = 2hrs

Step-by-step explanation:

Firstly, to outline some variables, with which we can construct some equations:

x = the time taken to cross the river at 10mph (in hrs)

y = the time taken to cross the river at 5mph (in hrs)

t = total time taken to cross the river (in hrs)

a = distance travelled at speed 10mph (in miles)

b = distance travelled at speed 5mph (in miles)

Then,

a + b = 15

t = x + y

y = ¹/₂(t) ∴ t = 2y, so,

x + y = 2y ∴ x = y

Secondly, we know speed = distance/time, so,

10 = a/x ⇒ x = a/10

5 = b/x ⇒ x = b/5

So,

a/10 = b/5 ∴ a = 2b

Thirdly, if a + b = 15, then,

2b + b = 15 ⇒ 3b = 15 ⇒ b = 5

[a = 2b ∴ a = 10]

Fourthly, x = b/5, so,

x = 5/5 = 1,

Since x = y, y = 1 and since t = 2y,

t = 2(1) = 2

The whole trip, therefore, took 2hrs.

5 0
3 years ago
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