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12345 [234]
3 years ago
11

The information is in the picture PLEASE HELP ME

Mathematics
1 answer:
Dima020 [189]3 years ago
7 0

Answer:

The answer is B.

Step-by-step explanation:

x^2-5x = x + 5

(x^2-5x)( x + 5)

x^3 - 25x^2+25x^2-25x

x^3 - 25x

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The volumes of two similar figures are given. The surface area of the larger figure is given. Find the surface area of the small
frez [133]

Answer:

surface area of the smaller figure ≈ 1474.64 m²

Step-by-step explanation:

The figures are similar base on the question . The surface area and the volume of the larger figure is given while only the figure of the smaller figure is given.

To find the surface area of the smaller figure we simply use the ratios. That is the scale factors.

Therefore, they are similar figure the scale factor  can be represented as a:b.

The scale factor for volume is cubed.

volume of larger figure/volume of the small figure = a³/b³

4536/2625 = a³/b³

a/b = 16.5535451/13.7946209

Note that for two similar solid with scale factor a:b the surface area ratio is a²: b² (the scale factor is square)

16.55²/13.79² = 2124/x

273.9025/190.1641 = 2124/x

cross multiply

273.9025x = 403908.54840

x = 403908.54840/273.9025

x = 1474.6435261

x ≈ 1474.64 m²

4 0
3 years ago
PLEASE HELP <3
quester [9]

Answer:

-403/40

or

-10 3/40

or

-10.075

3 0
2 years ago
Read 2 more answers
Rewrite the expression ln(33^3)+ln(9^4) so that it includes the expressions ln(3) and 33 and 9 do not appear inside a natural lo
krok68 [10]

Answer:

In Section 6.1, we introduced the logarithmic functions as inverses of exponential functions and

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We first extract two properties from Theorem 6.2 to remind us of the definition of a logarithm as

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Step-by-step explanation:

Hope this helps

4 0
3 years ago
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nydimaria [60]

Answer:

the top and bottom ones

Step-by-step explanation:

7 0
3 years ago
Dan has 18 chocolates. Lee has 14 chocolates. How many fewer<br> chocolates does Lee have?
artcher [175]

Answer:

4 Fewer Chocolates

Step-by-step explanation:

18-14=4

8 0
3 years ago
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