suppose you wanted the tank to hold 100 gallons of water and it was 50 gallons per cubic feet. How many cubic feet would you need? Obviously, 2 cubic feet. How did you get that?? Well, you divided 100 by 50 to get 2.
O.K., now, let's try YOUR problem. 225000 gallons and 7.5 gallons per cubic feet. How many cubic feet do you need? Must be 225,000/7.5 = 30,000 cubic feet
O.K., now we're half way there. we (should) know that the volume of a prism is
l x w x h. We now know the volume must also be 30,000
so l x w x h = 30000
100 x 20 x h = 30000
you should be able to take it from there.
Problem #2
We approach it the exact same way.
It's too hard as stated. Let's make up an easier problem.
suppose 1 gallon took up 5 cubic feet. If you had 10 cubic feet, how many gallons would you have?
well, clearly, you would have 2 gallons. How did you get it?
Now, how many cubic feet in the cylinder? Well you (should) know that the volume of a cylinder is:
Pi r^2h = 3.14 x 25^2 h = 1962.5 h
Now we have a bit of a problem. You didn't tell me how high the tank is. Let us say it is 10 feet.
So, the tank had 19,625 cubic feet.
Go back to the start of this problem and you will know what to do next.
You will need exactly 128 pieces of candy to go on all the cookies.
Step-by-step explanation:
To get to this conclusion you will need to use multiplication to determine the outcome.
Since there are 32 cookies for 8 of your friends and each cookie needs 4 pieces of candy you will need to multiply the pieces of candy per cookie.
32×4=128
Each friend will get 4 cookies each. You will get this conclusion by using division.
32÷8 = 4
Learn more about multiplication at brainly.com/question/12353086
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Answer:
Step-by-step explanation:
2x = 90
x = 45
45 and 45
Answer:
c × 0.90
Step-by-step explanation:
c × 0.90, would be your answer because 10% is equal to 0.10, then you would subtract the 0.10 (10%) by 1 (100%), then multiply c times the 0.90 that you get, to get the decreased number, because you're multiplying by a decimal
Answer:
Step-by-step explanation: