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lawyer [7]
3 years ago
12

Three flavors of juice are offered at a school cafeteria. The table shows the number of students who purchased each flavor durin

g three lunch periods.
Based on the table, what is the probability that a student who bought juice chosen at random purchased the grape flavor?

Orange-51
Grape- 30
Cherry-69

A. 0.2
B. 0.25
C. 0.3
D. 0.33
Mathematics
2 answers:
Viefleur [7K]3 years ago
8 0
The correct answer is .2
30 out of 150 is equal to 20%, therefore in decimals, the answer is .2
Sonbull [250]3 years ago
5 0

Answer:

0.25

Step-by-step explanation:

Based on my knowledge of math sorry if its wrong

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Cherry and Tyler have been collecting video games. Cherry has 35 video games, and Tyler has v video games. Together they have a
sergey [27]

Answer:

V=40

Step-by-step explanation:

75-35=40

3 0
3 years ago
A case in riverhead, new york, nine different crime victims listened to voice recordings of five different men. all nine victims
Alexus [3.1K]

the complete question in the attached figure

1) Find the probability that all nine victims would select the same person. You should enter your answer as a decimal, not as a percent. Do not round, as your answer should be a terminating decimal.

P=(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)=0.000000512

2) what is the probability that the first victim picks SOMEONE? ANYONE? 

P=(1/5)=0.20  ---------------- > 20%

3) Now let’s look at victim #2. What is the probability that they pick the same person as victim #1?

P=(1/5)*(1/5)=0.04 --------------> 4%

4) Now let’s look at victim #3. What is the probability that they pick the same person as victim #1?

P=(1/5)*(1/5)*(1/5)=0.008 --------------> 0.8%

5) Now let's look at victim #9. What is the probability that they pick the same person as victim #1? 

P=(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)=0.000000512

6) Once you find all those probabilities, what rule would apply?

the probability is given by (1/5)^n

n=number of victims that pick the same person---------> in this problem = 9

P=(1/5)^9= 0.000000512

5 0
3 years ago
Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th
grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

S = \{1,1,2,2,2,3\}

And the probability of each is:

P(1) = \frac{n(1)}{n(s)}

P(1) = \frac{2}{6}

P(1) = \frac{1}{3}

P(2) = \frac{n(2)}{n(s)}

P(2) = \frac{3}{6}

P(2) = \frac{1}{2}

P(3) = \frac{n(3)}{n(s)}

P(3) = \frac{1}{6}

P(Odd Number) is then calculated as:

P(Odd\ Number) =  P(1) + P(3)

P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}

Take LCM

P(Odd\ Number) = \frac{2+1}{6}

P(Odd\ Number) = \frac{3}{6}

P(Odd\ Number) =  \frac{1}{2}

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

S = \{1,1,2,2,2,3,3\}

The probability of each is:

P(1) = \frac{n(1)}{n(s)}

P(1) = \frac{2}{7}

P(2) = \frac{n(2)}{n(s)}

P(2) = \frac{3}{7}

P(3) = \frac{n(3)}{n(s)}

P(3) = \frac{1}{7}

P(Odd\ Number) = P(1) + P(3)

P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}

Take LCM

P(Odd\ Number) = \frac{2+1}{7}

P(Odd\ Number) = \frac{3}{7}

Comparing P(Odd Number) before and after

P(Odd\ Number) =  \frac{1}{2} --- Before

P(Odd\ Number) = \frac{3}{7} --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0
3 years ago
-2(7a+ 9b) = –14a + [?]b
OverLord2011 [107]

Answer:

-18

Step-by-step explanation:

Left Hand Side = -2(7a + 9b) = -14a - 18b

Comparing it with Right Hand Side, ?  = -18

3 0
2 years ago
Read 2 more answers
the volume of a cone is 62.28 cubic inches. The height of the cone is 15 inches. What is the radius of the cone, rounded to the
fiasKO [112]

Answer:

The radius of cone is: 3 inches

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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