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3 years ago

Graph h(x)=-x^4 +3

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

8 0

Hope this helps, the y intercept is 3 ans the x intercepts are +1.3 and -1.3

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Find f(-10) f(x)=7x-5

Inessa [10]

Answer:

Step-by-step explanation:

F(x) is simply another way of saying y. We are given the x value of -10. We can substitute this in for x and find y.

f(-10) = 7(-10) - 5

f(-10) = -70 - 5

f(-10) = -75

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3 years ago

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RideAnS [48]

Answer:

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Step-by-step explanation:

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Finding an Equation of a tangent Line in Exercise, find an equation of the tangent line to the graph of the function at the give

frutty [35]

Answer:

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

$g(x) =e^{x^3}$

we know that $\frac{d}{dx}(e^{f(x)})=e^{f(x)}f'(x)$

$g'(x) =e^{x^{3}}(3 x^{2})$

$g'(x) =3 x^{2} e^{x^{3}}$

this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

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$m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}$

using the equation of line:

$(y-y_1)=m(x-x_1)$

we'll find the equation of the tangent line.

here (x1,y1) =(-1,1/e), and m = 3/e

$(y-\dfrac{1}{e})=\dfrac{3}{e}(x+1)\\y=\dfrac{3x}{e}+\dfrac{3}{e}+\dfrac{1}{e}\\$

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

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3 years ago

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Answer:

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I am going to rate how well the food is in this restaurant.

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