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boyakko [2]
4 years ago
14

Which of the following statements are true?

Mathematics
1 answer:
lara31 [8.8K]4 years ago
7 0

I believe it is C, as the graphs do look the same.

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Expand the following expression
masya89 [10]

Answer:

\frac{5}{4}  \times 4x +  \frac{5}{4}  \times  \frac{3}{4}  = 5x +  \frac{15}{16}

5 0
3 years ago
For EASY BRAINLIEST!!! <br><br> Answer:<br> A.<br> B.<br> C.<br> D. <br><br> On both questions
tekilochka [14]

Answer:

8a) 3x

8b) 3 × x

8c) (2/3)x

8d) x/2

8e) 1/x

9a) 4x - 7

9b) x + 1/x

9c) 5(x + 2)

9d) x/(x + 4)

9e) (x/8) + x

4 0
3 years ago
You are going to roll two dice. Let the variable x = the sum of the numbers rolled. What is the probability that x = 9 ?
Vladimir79 [104]

The  first cube can land in any one of  6  ways.
The  second cube can land in any one of  6  ways.
Total number of ways that  2 dice can land = (6 x 6) = 36 ways.

For any of these ways, the sum of the numbers rolled is  9 :

3, 6
4, 5
5, 4
6, 3

There are  4  ways to roll a 9, out of a total of  36  ways that
the dice can land.  So the probability of rolling a  9  is

       4 / 36  =  1 / 9  =  <em>11-1/9 percent</em>


7 0
3 years ago
Question is below in photo
horrorfan [7]

what about using 20-30-40-5

Step-by-step explanation:

the sequence is that you are skipping ten to get the second nb which is 30 and keep on going on to get 50

3 0
3 years ago
Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)
Dima020 [189]

Split C into two component segments, C_1 and C_2, parameterized by

\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)

\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)

respectively, with 0\le t\le1, where \mathbf r_i(t)=(x(t),y(t)).

We have

\mathrm d\mathbf r_1=(6,1)\,\mathrm dt

\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt

where \mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt

so the line integral becomes

\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)

=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt

=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6

6 0
3 years ago
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