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3 years ago

11

In making a keychain,Sara uses a pattern of beads 3 times. After the key chain is complete, what fraction of the beads in the ke

y chain are either blue or red ?

1 answer:

nikdorinn [45]3 years ago

3 0

1/2 of the beads will be blue, and 1/2 of them would be red Hope this helped!

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6x+2y=<br> −10 <br> slope int form

valentinak56 [21]

Answer:

y = -3x -5

Step-by-step explanation:

Slope intercept form is

y = mx+b where m is the slope and b is the y intercep

6x+2y = -10

Subtract 6x from each side

6x+2y -6x = -6x-10

2y = -6x-10

Divide each side by 2

2y/2 = -6x/2 -10/2

y = -3x -5

7 0

2 years ago

Read 2 more answers

Xander has 10 pieces of twine that he is using for a project. If each piece of twine is 1/3 yard long, what is the total length

vovikov84 [41]

1 yard (3/3) is equal to 3 feet, then 10/3 is equals to 10 feet

8 0

4 years ago

Create a set of coordinates to model a relation that is a linear function.

STALIN [3.7K]

I will create a set of arbitrary constants (x1,y1) (x2,y2)

slope = y2-y1/x2-x1

y = (y2-y1/x2-x1)x + b

y2 = (y2-y1/x2-x1)x2 + b

b = y2 - (y2-y1/x2-x1)x2

y = (y2-y1/x2-x1)x + [y2 - (y2-y1/x2-x1)]

Choose any points and just
Plug the values and you have a linear function.

NOT SURE IF THAT'S WHAT THE QUESTION WANTS.

3 0

3 years ago

Given right triangle jkl, what is the value of cos(l)?

miss Akunina [59]

Taking K as the right angle =>

cos (L) = segment LK / hypotenuse

=> cos(L) = segment LK / √ [ (segment LK)^2 + (segment KJ)^2 ]

7 0

3 years ago

The compressive strength of concrete is normally distributed with mu = 2500 psi and sigma = 50 psi. A random sample of n = 8 spe

ipn [44]

Answer:

The standard error of the sample mean is _17.677_ psi.

Step-by-step explanation:

<u>Explanation</u>:-

A random sample of n = 8 specimens is collected.

Given sample size is n = 8

Given mean of the population 'μ' = 2500 psi

standard deviation 'σ' = 50 psi

Let x⁻ is the mean of the observed sample

Standard error of the sample mean = $\frac{S.D}{\sqrt{n} }$ ...(i)

Given Population of standard error (S.D) 'σ' = 50 psi

Now substitute all values in (i)

$S.E = \frac{50}{\sqrt{8} } =17.677$

<u>Conclusion</u>:-

The standard error of the sample mean is _17.677psi.

7 0

3 years ago