<span><span> 4c2+6c-3c2-2c-3</span> </span>
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "c2" was replaced by "c^2". 1 more similar replacement(s).
Step by step solution :<span>Step 1 :
</span><span>Equation at the end of step 1 :</span><span><span> ((((4•(c2))+6c)-3c2)-2c)-3
</span><span> Step 2 :</span></span><span>Equation at the end of step 2 :</span><span> (((22c2 + 6c) - 3c2) - 2c) - 3
</span><span>Step 3 :</span>Trying to factor by splitting the middle term
<span> 3.1 </span> Factoring <span> c2+4c-3</span>
The first term is, <span> <span>c2</span> </span> its coefficient is <span> 1 </span>.
The middle term is, <span> +4c </span> its coefficient is <span> 4 </span>.
The last term, "the constant", is <span> -3 </span>
Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 1</span> • -3 = -3</span>
Step-2 : Find two factors of -3 whose sum equals the coefficient of the middle term, which is <span> 4 </span>.
<span><span> -3 + 1 = -2</span><span> -1 + 3 = 2
</span></span>Final result :<span> c2 + 4c - 3 </span>
