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puteri [66]
3 years ago
7

4C2 + 6C + 3C2 - 2C - 3

Mathematics
1 answer:
Gnesinka [82]3 years ago
3 0
<span><span> 4c2+6c-3c2-2c-3</span> </span>

Reformatting the input :

Changes made to your input should not affect the solution:

 (1): "c2"   was replaced by   "c^2".  1 more similar replacement(s).

Step by step solution :<span>Step  1  :
</span><span>Equation at the end of step  1  :</span><span><span> ((((4•(c2))+6c)-3c2)-2c)-3 </span><span> Step  2  :</span></span><span>Equation at the end of step  2  :</span><span> (((22c2 + 6c) - 3c2) - 2c) - 3 </span><span>Step  3  :</span>Trying to factor by splitting the middle term

<span> 3.1 </span>    Factoring <span> c2+4c-3</span> 

The first term is, <span> <span>c2</span> </span> its coefficient is <span> 1 </span>.
The middle term is, <span> +4c </span> its coefficient is <span> 4 </span>.
The last term, "the constant", is <span> -3 </span>

Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 1</span> • -3 = -3</span> 

Step-2 : Find two factors of  -3  whose sum equals the coefficient of the middle term, which is  <span> 4 </span>.

<span><span>     -3   +   1   =   -2</span><span>     -1   +   3   =   2
</span></span>Final result :<span> c2 + 4c - 3 </span>
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