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kirill115 [55]
3 years ago
8

A sphere and a cylinder have the same radius and height. The volume of the cylinder is 30 m3

Mathematics
2 answers:
vfiekz [6]3 years ago
3 0
Volume of cylinder  = pi r^2 h  = 30 m^3
Volume of sphere = 4/3 pi r^3
now h = 2r ( given) 
so volume of cylinder = pi r^2 * 2r  = 2 pi r^3 = 30
pi r^3 = 15  so r^3  = 15/pi 

therefore the volume of sphere = 4/3 pi * 15/pi = 4/3 * 15 = 20  m^3  Answer
jok3333 [9.3K]3 years ago
3 0

Answer:

Option B is correct

20 m^3

Step-by-step explanation:

Volume of the sphere(V) is given by:

V = \frac{4}{3} \pi r^3;     .....[1] where, r is the radius of the sphere.

Volume of cylinder(v') is given by:

V'= \pi r'^2h'

where, r' is the radius of the cylinder and h' is the height of the cylinder

As per the statement:

A sphere and a cylinder have the same radius and height.

r = r'

h = 2r = h'

It is also given that:  The volume of the cylinder is 30 m^3

⇒V' = \pi r'^2h'

⇒ 30 = \pi r^2 \cdot (2r)

⇒ 30 = 2 \pi r^3

Divide both sides by 2 we have;

15 = \pi r^3

Substitute in [1] we have;

V = \frac{4}{3} \cdot 15

Simplify:

V = 20 m^3

Therefore, volume of sphere is, 20 m^3

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If tan2A=cot(A+60), find the value of A, where 2A is an acute angle
jeka57 [31]

Answer:

Here  the answer is 10=a

Step-by-step explanation:

= Tan 2A = cot(A+60°)

= cot(90-2A) = cot (A+60°)

= 90°-2A = A+60°

= 90°-60° =A+2A

= 30 = 3A

= 30\3 = A

= 10 = A

Hope it helps you and plz mark as brainliest..☺


7 0
3 years ago
Lines CD and DE are tangent to circle A, as shown below:Lines CD and DE are tangent to circle A and intersect at point D. Arc CE
Charra [1.4K]

Answer:

55°

Step-by-step explanation:

Given that;

Lines CD and DE are tangent to circle A and intersect at point D.

and:

Arc CE measures 125 degrees. Point B lies on circle A.

There lies a diagrammatic representation below given a clear picture of what this question looks like;

If arc CE is 125°, what is the measure of ∠CDE?

SO, by using the outside angle theorem

∠CDE = \frac{CBE-CE}{2}

where arc CE = 125°

we can determine CBE  by subtracting it from angle of a circle = 360°

Thus, CBE = 360° - 125°

CBE = 235°

Again; ∠CDE = \frac{CBE-CE}{2}

∠CDE = \frac{235^0-125^0}{2}

∠CDE = \frac{110^0}{2}

∠CDE = 55°

∴ The measure of ∠CDE = 55°

4 0
3 years ago
Turn 294% to a fraction
damaskus [11]
294% as a fraction is 294/100
This is an improper fraction. 

Hope this helps :)
8 0
3 years ago
Read 2 more answers
(05.04 MC) An image of a rectangular pyramid is shown below: A right rectangular pyramid is shown. Part A: A cross section of th
sleet_krkn [62]

Answer:

Part a) Rectangle

Part b) Triangle

Step-by-step explanation:

Part A) A cross section of the rectangular pyramid is cut with a plane parallel to the base. What is the name of the shape created by the cross section?

we know that

When a geometric plane slices any right pyramid so that the cut is parallel to the plane of the base, the cross section will have the same shape (but not the same size) as the base, So, in the case of a right rectangular pyramid, the cross section is a rectangle

Part b)  If a cross section of the rectangular pyramid is cut perpendicular to the base, passing through the top vertex, what would be the shape of the resulting cross section?

we know that

Cross sections perpendicular to the base and through the vertex will be triangles

5 0
2 years ago
Which of the following tables shows the correct steps to transform x2 + 10x + 24 = 0 into the form (x − p)2 = q? [p and q are in
IRINA_888 [86]
1.
x² +10x +24 = 0
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2.
x² +2*5*x +5² =-24+5²
3.
x²+2*5*x+25 = -24+25
4.
(x+5)² = 1
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8 0
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