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Nonamiya [84]
3 years ago
13

7. Maria quiere agrandar la foto de su

Mathematics
1 answer:
lukranit [14]3 years ago
7 0

Answer:

the perimeter is 960

Step-by-step explanation:

The computation of the perimeter is shown below;

If we assume

= (24 × 2) + (6 × 2)

= 48 + 12

= 60

And, the area is 16 times to that of original So

= 60 × 16

Hence, the perimeter is 960

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Lamar is solving the equation x2−12x=−6 by completing the square. Which shows Lamar's next step and the solution to the equation
Levart [38]
Completing the square is a process to find the solutions, or the x-values, to a quadratic equation. This method can only work if it is in the format: x^2 + bx = c
In this equation, the b value is -12 and the c value is -6. The process for completing the square goes like this:

x^2 + bx + (b/2)^2 = c + (b/2)^2

Now let’s solve the equation above using this method.

Step 1: x^2 - 12x + (-12/2)^2 = -6 + (-12/2)^2

Step 2: x^2 - 12x + (-6)^2 = -6 + (-6)^2

Step 3: x^2 - 12x + 36 = -6 + 36

Step 4: x^2 - 12x + 36 = 30

Now, to factor it. After doing the process until now, the left side of the equation can ALWAYS be in the format: (x + a)^2

Step 5: x^2 - 12x + 36 can be factored in this format as (x - 6)^2

Step 6: (x - 6)^2 = 30

Step 7: x - 6 = √30

Step 8: x = 6 ±√30

4 0
2 years ago
Multiply 1 5.8 and 5.62
Maurinko [17]

Answer:

88.796

Step-by-step explanation:

you multiply them...

3 0
3 years ago
Read 2 more answers
Nigel travels a total of 312 miles to school each day. He walks 14 mile to the bus stop. He travels 234 miles on the city bus. I
Valentin [98]
The bus drops Nigel off 64 miles away from the school.

Step by step Explanation:

An equation for this would be 312-14-234 (this was the equation I used. Since you would do left to write to solve the equation, you would do, 312-14 which equals 298. Then, the equation is left as 298-234, and when you solve that part to the equation, yoh would be getting 64. And that's how you would get the answer 64miles away from the school.
7 0
3 years ago
Electricity usage data consists of 45 months has a mean number of units consumed is 390.47 per month with a standard deviation o
neonofarm [45]

Answer:

The 95% confidence interval for the average monthly electricity consumed units is between 47.07 and 733.87

Step-by-step explanation:

We have the standard deviation for the sample. So we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 45 - 1 = 44

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 44 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.0141

The margin of error is:

M = T*s = 2.0141*170.5 = 343.4

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 390.47 - 343.40 = 47.07 units per month

The upper end of the interval is the sample mean added to M. So it is 390.47 + 343.40 = 733.87 units per month

The 95% confidence interval for the average monthly electricity consumed units is between 47.07 and 733.87

6 0
3 years ago
8. A triangle has sides with lengths of 6, 8, and 10 units, and a square has a
svet-max [94.6K]

Difference between the area of the triangle and square is 25

Step-by-step explanation:

  • Step 1: Find the area of the triangle given its 3 sides using the Heron's formula.

Area of the triangle = \sqrt{s (s-a)(s-b)(s-c)} where s = \frac{a + b + c}{2}

⇒ s = (6 + 8 + 10)/2 = 24/2 = 12

\sqrt{s(s-a)(s-b)(s-c)} = \sqrt{12(12-6)(12-8)(12-10)}

                                    = \sqrt{12(6)(4)(2)} = \sqrt{576} = 24 sq. units

  • Step 2: Find the area of the square with perimeter = 28 units.

Perimeter of the square = 4 × side = 28

⇒ Side of the square = 28/4 = 7 units

⇒ Area of the square = (side)² = 7² = 49 sq. units

  • Step 3: Find the difference between the area of the square and triangle.

Difference = 49 - 24 = 25

8 0
3 years ago
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