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Blababa [14]
3 years ago
9

(14+3)–7=NPerform te indicated operations​

Mathematics
1 answer:
Anastaziya [24]3 years ago
8 0
10=N I’m not 100% sure hope this helped :)
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Is 7/12 bigger than 1/2
Varvara68 [4.7K]
Lets think of it this way:-

1/2 is one half

Whats half of 12? 6 

Now, 7 is greater than 6, which means the fraction 7/12 is greater than 1/2

Answer: 7/12 is bigger 
7 0
3 years ago
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Can u guys help me please
vesna_86 [32]
1.) 25%
2.) 75%
3.) 25
5 0
3 years ago
Solve the equation by completing the square.<br><br> 3x^2 -6+9=0
Debora [2.8K]
The factored form would be (3x-9)(x-1)
The picture should help a bit
8 0
3 years ago
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2y=-x+9<br>3×-6y=-15 whats the solution to the system​
liq [111]

Answer:

Step-by-step explanation:

2y = -x +9

3x - 6y = -15

The solution is the value of x and y that will make the two equations true in the same time.

3x-6y = -15;  divide both sides by 3

x-2y = -5; substitute 2y for -x+9 because the first equation tell us they are equal

x-(-x+9) = -5; open parenthesis

x+x-9 = -5 ; add 9 to both sides  and combine like terms

2x = -5 +9; 2x = 4; divide both sides by 2

x= 2

Substitute x for 2

2y = -x+9 ; 2y = -2 +9 ; 2y = 7; y = 7/2 = 3.5

Solution is (2, 3.5)

8 0
3 years ago
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Which of the following functions have a vertical asymptote for values of Ø such that cos Ø = 1?Select all that apply.
igomit [66]

Answer:

y=\cot \theta and y=\csc \theta

Step-by-step explanation:

Note that if \cos \theta=1, then \sin \theta=0.

Functions y=\cos \theta,\ \ y=\sin \theta do not have vertical asymptotes at all.

Vertical asymptotes have functions y=\tan \theta,\ \ y=\cot \theta,\ \ y=\sec \theta,\ \ y=\csc \theta.

Functions y=\tan \theta and y=\sec \theta have the same vertical asymptotes (when \cos \theta =0).

Functions y=\cot \theta and y=\csc \theta have the same vertical asymptotes (when \sin \theta =0). See attached diagram

3 0
3 years ago
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