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LiRa [457]
3 years ago
14

Helpppp it’s so hard and due today pleaseee

Mathematics
1 answer:
gladu [14]3 years ago
8 0

Answer:

for every 2 followers benjamin has, lauren has 5 followers

Step-by-step explanation:

find the common factor for their followers (11), then divide them by that:

22/11=2

55/11=5

You might be interested in
Which expression is equivalent to 6x^2+16x-6
AveGali [126]

The answer is (2x+6)(3x-1)

6 0
3 years ago
Before the distribution of certain statistical software, every fourth compact disk (CD) is tested for accuracy. The testing proc
lilavasa [31]

Answer:

a) For this case we have 4 programs so then if we define the event R that a CD is tested we have the following probability for each test:

P(R) =\frac{1}{4} =0.25

The failure probability for each program are given by:

P(F_1) = 0.01 , P(F_2) = 0.03 , P(F_3) = 0.02 , P(F_4) = 0.01

For this case we assume that each test is independet form the others.

We can calculate the probability that all 4 programs works properly like this:

P(4 work) = (1-0.01)*(1-0.03)*(1-0.02)*(1-0.01)= 0.932

So then the probability that any program fails would be given by:

P(F) = 1- 0.932= 0.068

And if we use the fact that we have 4 possible test the true probability of interest would be:

P(R \cap F) = P(R)*P(F) = 0.25*0.068=0.017

b) p= P(F'_1) P(F'_4) *(1- P(F'_2)*P(F'_3))

And replacing we got:

p =(1-0.01)*(1-0.01) *[1- (1-0.03)(1-0.02)]= 0.99*0.99*[1- 0.97*0.98]= 0.0484

c) From part a we now that the probability that any program fails would be given by:

P(F) = 1- 0.932= 0.068

So then if we have 100 CDs the expected number of rejected Cd's are:

100*0.068= 6.8 \approx 7

Step-by-step explanation:

Part a

For this case we have 4 programs so then if we define the event R that a CD is tested we have the following probability for each test:

P(R) =\frac{1}{4} =0.25

The failure probability for each program are given by:

P(F_1) = 0.01 , P(F_2) = 0.03 , P(F_3) = 0.02 , P(F_4) = 0.01

For this case we assume that each test is independet form the others.

We can calculate the probability that all 4 programs works properly like this:

P(4 work) = (1-0.01)*(1-0.03)*(1-0.02)*(1-0.01)= 0.932

So then the probability that any program fails would be given by:

P(F) = 1- 0.932= 0.068

And if we use the fact that we have 4 possible test the true probability of interest would be:

P(R \cap F) = P(R)*P(F) = 0.25*0.068=0.017

Part b

For this case we want the probability that it failed program 2 or 3

So then we can find this probability like this:

p= P(F'_1) P(F'_4) *(1- P(F'_2)*P(F'_3))

And replacing we got:

p =(1-0.01)*(1-0.01) *[1- (1-0.03)(1-0.02)]= 0.99*0.99*[1- 0.97*0.98]= 0.0484

Part c

From part a we now that the probability that any program fails would be given by:

P(F) = 1- 0.932= 0.068

So then if we have 100 CDs the expected number of rejected Cd's are:

100*0.068= 6.8 \approx 7

3 0
3 years ago
Need help please anyone
kifflom [539]
Which question do you need help with
5 0
3 years ago
Could someone help me solve this problem?
Ann [662]

Answer:

\boxed{x=58} & \boxed{m \angle C = 60}

Step-by-step explanation:

You need to find x first in order to find the measure of angle C. To solve for x, we will use the fact that interior angles of a triangle have angle measurements that add up to 180 degrees.

Using this knowledge, we can create an equation where angles A, B, and C add up to equal 180.

  • A+B+C=180
  • (x+4)+(x)+(x+2)=180

Combine like terms on the left side of the equation.

  • 3x + 6 = 180

Subtract 6 from both sides of the equation.

  • 3x=174

Divide both sides of the equation by 3.

  • x=58

Now that you've found the value of x, you can use this value to plug into the expression for angle C.

  • C=x+2
  • C=(58)+2
  • C=60

Therefore, the final answer is:

x=58\  \text{and} \ m \angle C = 60

4 0
3 years ago
Read 2 more answers
I WILL GIVE BRAINLIEST!! PLEASE HURRY
crimeas [40]

Answer:

B. It rejects the concept of social class in the American system.

Explanation:

The Enlightenment of the American Colonies was a period in time where the people were encouraged to become their own nation. This period was represented by many speeches and pieces of writing that boasted freedom of speech, equality, freedom of the press, and religious tolerance.

This specific piece of writing focuses on the aspect of all people in the nation of America having protected freedoms and rights to become their own people.

5 0
3 years ago
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