the square root of 3 and the square root of 5 because they are both decimals.
They are both simple exercises in addition.
The solutions are:
(-65) x (-2) = <em>130</em>
(5j) + (10j) =<em> 15j</em>
Answer:
C. 15²π
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Geometry</u>
- Diameter: d = 2r
- Area of a Circle: A = πr²
Step-by-step explanation:
<u>Step 1: Define</u>
d = 30 m
<u>Step 2: Find Area</u>
- Substitute [D]: 30 m = 2r
- Isolate <em>r</em>: 15 m = r
- Rewrite: r = 15 m
- Substitute [AC]: A = π(15 m)²
- Rearrange: A = 15²π
Answer:
Step-by-step explanation:
2x+5y=12
3x+4y=11
---------------
3(2x+5y)=3(12)
-2(3x+4y)=-2(11)
-----------------------
6x+15y=36
-6x-8y=-22
-----------------
7y=14
y=14/7=2
2x+5(2)=12
2x+10=12
2x=12-10=2
x=2/2=1
x=1, y=2. (1, 2)
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I just provided you an example of a system of equations and I already solved it for you.
Hm, D would equal either 5 or 6.
