Answer:
D: The maximum value is 0
Step-by-step explanation:
Choice A is true because the x-intercepts are shown on the graph and are both -2 and 2.
Choice B is true because the parabola intercepts the y axis at 2.
Choice C is true because the AoS runs down the vertex which happens to be on the point (0,2).
Choice D is false because this parabola has no maximum value (parabolas continue forever unless stated otherwise).
Answer:
(a) 95% confidence interval for the percent of all adults who want to lose weight is (48%, 54%) that is between 48% and 54%
(b) to say that we have 95% confidence in this interval means that there is 95% chance that the true percentage of all adults who wants to lose weight falls in this interval.
Step-by-step explanation:
The question is missing, complete question is below:
A Gallup Poll found that 51% of the people in its sample said "yes" when asked, "Would you like to lose weight?" Gallup announced: "With 95% confidence for results based on the total sample of national adults, one can say that the margin of sampling error is ± 3%."
(a) What is the 95% confidence interval for the percent of all adults who want to lose weight?
(b) What does it mean to say that we have 95% confidence in this interval?
Confidence Interval can be calculated using p±ME where
- p is the sample proportion of national adults who want to lose weight (51%)
- ME is the margin of sampling error (± 3%)
Answer:
sewesdxfcv bghyjuukkkkkkkkkkkkkkkkkk1234567890-
Step-by-step explanation:
=-9[piojkhlbjvh gcfxsae vndhgcnboiybsgdtjygncvnftu
Answer
Step by step explanation
We experienced a lot of difficulties when submitting the answer to this question due to technical issues. Please check the files below to show how we have computed them. We make sure to made screenshots right here showing the step by step process to solve the question and also attached a word document for the question
Answer:
There will be 3472 cats in 10 years
Step-by-step explanation:
There were 3500 cats
The number of dogs in a city is declining at a rate of about 0.08% each year.
We are supposed to find the no. of cats in 10 years
Formula :
Where N(t) = Remaining cats after t days
= Initial population
r = rate of depreciation
t=time
So, No. of cats remained after 10 years = 
Hence There will be 3472 cats in 10 years
