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lina2011 [118]
4 years ago
15

Hey i have no idea what im doing someone help

Mathematics
1 answer:
yan [13]4 years ago
8 0

Answer:

ok me so basically

Step-by-step explanation:

the x axis is the one that goes left to right, so every number thats on the x side of the table, thats how far you go left or right. the y axis goes up and down so every number on the y side of the table is how much you go up and down. this problem is seeing if the graph corresponds with the table, it doesnt bc if it did, the part where it goes through the y axis would be right at 2 and up 0.

so basically with all that, no the table doesnt check out.

this was a very basic amateur explanation but if you have any questions i can answer them in the comments

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Solve for x. 4(2-x)+13=2x+3
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Answer:

x = 3

Step-by-step explanation:

4(2-x)+13=2x+3

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8 - 4x + 13 = 2x + 3

combine like terms.

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Make COS the subject of the formula
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3 years ago
What’s the answer PLZ???
ollegr [7]
11. Take the logarithm, base X.
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3 years ago
Reflect the given preimage over y=−1 followed by y=−7. Find the new coordinates. What one transformation is this double reflecti
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Answer:

Reflecting over y = -1 line:

A'(8, -10)

B'(10, -8)

C'(2, -4)

Reflecting over y = -7 line:

A''(8, -4)

B'(10, -6)

C''(2, -10)

Step-by-step explanation:

Reflect the given preimage over y=−1 followed

by y=−7. Find the new coordinates. What one transformation is this double reflection the same as? (Note: when you are reflecting over a y= line, the x-values of the preimage will remain the same and you will be changing the y-values)

The coordinates of the preimage are:

A(8,8)

B(10,6)

C(2,2)

Answer: Reflecting over y = -1:

If a point is reflected over a y line, the x values remain the same while the y values change.

For point A(8, 8): The y distance between the y = - 1 line and point A is 9 units. (8- (-1)). If point A is reflected, the y value would be 9 units below the y = -1 line, i.e the new y coordinate would be at -10 (-1-9)

The new coordinate is at A'(8, -10)

For point B(10, 6): The y distance between the y = - 1 line and point B is 7 units. (6- (-1)). If point B is reflected, the y value would be 7 units below the y = -1 line, i.e the new y coordinate would be at -8 (-1-7)

The new coordinate is at B'(10, -8)

For point C(2, 2): The y distance between the y = - 1 line and point C is 3 units. (2- (-1)). If point C is reflected, the y value would be 3 units below the y = -1 line, i.e the new y coordinate would be at -4 (-1-3)

The new coordinate is at C'(2, -4)

Reflecting over y = -7 line:

For point A'(8, -10): The y distance between the y = - 7 line and point A' is 3 units. (-7- (-10)). If point A' is reflected, the y value would be 3 units above the y = -7 line, i.e the new y coordinate would be at -4 (-7+3)

The new coordinate is at A''(8, -4)

For point B'(10, -8): The y distance between the y = - 7 line and point B' is 1 units. (-7- (-8)). If point B' is reflected, the y value would be 1 units above the y = -7 line, i.e the new y coordinate would be at -6 (-7 + 1)

The new coordinate is at B'(10, -6)

For point C'(2, -4): The y distance between the y = - 7 line and point C' is 3 units. (-4- (-7)). If point C' is reflected, the y value would be 3 units below the y = -7 line, i.e the new y coordinate would be at -10 (-7-3)

The new coordinate is at C''(2, -10)

We can also see that h= −7−(−1)=−6. We know that two reflections is the same as a translation of 2h  units down. So 2(−6) is a translation of −12 units down.

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3 years ago
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