Question

Consider the following reaction: 2 SO2(g) + O2(g) → 2SO3(g)

Answer 1

Answer:

B) -1.00 M/min

Explanation:

Based on the reaction:

2 SO2(g) + O2(g) → 2SO3(g)

2 moles of SO2 are consumed per mole of O2 producing 2 moles SO3

In the problem, the sulfur dioxide has a rate of change of -2.00M/min. As the moles of oxygen that reacted are half the moles of SO2, its rate of change is halved, that is:

B) -1.00 M/min