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iVinArrow [24]
3 years ago
10

Jay wants to know how the amount of acidity in rainwater influences the weathering rate of limestone.

Chemistry
2 answers:
lys-0071 [83]3 years ago
5 0

Answer:- To check the reliability of our experiments we repeat the experiment many times and see if we get the same results or almost same results.

It's also good to compare the results of two or more students for the same experiment and see if they get the similar results.

So, to improve the reliability and accuracy of the experimental data, Jay needs to repeat the experiment and also ask his one or more friends to do the experiment and record the data.

creativ13 [48]3 years ago
3 0
He can repeat his experiment multiple times, and ask a friend to repeat it as well to see if they get the same answer. 
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Consider the following reaction: . SO2Cl2(g)⇌SO2(g)+Cl2(g) . A reaction mixture is made containing an initial [SO2Cl2] of 2.2×10
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The equilibrium constant (Kc) is the product of the equilibrium concentrations of the products raised to their corresponding stoichiometric coefficients divided by the reactants as well. In this case the equilibrium concentration of Cl2 which also applies to SO2 is 1.3x10^-2. The final equilibrium concentration of SO2Cl2 is 9x10^-3. Kc is then equal to 0.0188.
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3 years ago
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What effect does the anion of an ionic compound have on the appearance of the solution?
choli [55]

Answer: B. The anion affects the color of the solution more than the intensity of the color.

Explanation:

An ionic bond is gotten when an electron is transferred from a metal atom to a non-metal one. It should be noted that the ionic bonds simply has an anion and a cation.

An anion is formed when a valence election is gained by a non metal while a cation is formed when the metal ion misplaces a valence electron.

The effect of the anion of an ionic compound on the appearance of the solution is that the anion affects the color of the solution more than the intensity of the color.

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2 years ago
Calculate the mass percent (m/m) of a solution prepared by dissolving 51.56 g of NaCl in 164.2 g of H2O. Express your answer to
denis-greek [22]

Answer:

"23.896%" is the right answer.

Explanation:

The given values are:

Mass of NaCl,

= 51.56 g

Mass of H₂O,

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As we know,

⇒  Mass of solution = Mass \ of \ (NaCl+H_2O)

                                 = 51.56+164.2

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hence,

⇒ Mass \ percent =\frac{Mass \ of \ NaCl}{Mass \ of \ solution}\times 100

                           =\frac{51.56}{215.76}\times 100

                           =23.896 \ percent

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