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4 years ago

Which has the greater polarizing power, Li+ or Be2+ and why?

Chemistry

1 answer:

kvasek [131]4 years ago

4 0

Answer:

Polarizing power refers to an atoms ability to pull an electron toward it, polarizing the atom the electron comes from. Since cations are positive, they are able to attract electrons toward themselves. Anions are negative and so do not attract more electrons.

Therefore, Be2+ has a higher polarizing power because it has a higher quantitiy of protons, hence a higher polarizing power.

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What volume of hydrogen gas is required to react with 113 liters of ethylene (C2H4) according to the following reaction? (All ga

AysviL [449]

Answer: The volume of hydrogen gas required for the given amount of ethylene gas is 113 L

Explanation:

At STP:

1 mole of a gas occupies 22.4 L of volume

We are given:

Volume of ethylene = 113 L

For the given chemical equation:

$H_2(g)+C_2H_4(g)\rightarrow C_2H_6(g)$

By Stoichiometry of the reaction:

$(1\times 22.4)L$ of ethylene reacts with $(1\times 22.4)L$ of hydrogen gas

So, 113 L of ethylene gas will react with = $\frac{(1\times 22.4)}{(1\times 22.4)}\times 113=113L$ of hydrogen gas

Hence, the volume of hydrogen gas required for the given amount of ethylene gas is 113 L

5 0

3 years ago

Pressure has the most influence on the solubility of which type of solute?

Scilla [17]

I think that pressure will affect the solubility of gasses the most. The reason why I think this is that gasses are affected the most by pressure change. By definition solids and liquids are not easily affected by pressure by how close the molecules are to each other in both of those phases.

I hope this helps. Please let me know if you have any further questions or need any clarification.

8 0

3 years ago

Read 2 more answers

If an element is on the 4th row of the periodic table...how many energy levels/rings would you need to draw a Bohr 's model of t

lana [24]

Answer:

4 energy levels/rings

Explanation:

By the atomic model proposed by Niels Bohr, the electrons orbit around the nucleus in shells having different energy level each with the ability to contain a given maximum amount of electrons.

The closest shell to the nucleus named the K shell, can have a maximum of two electrons, the next shell known as the L shell can have 8 electrons while the next shell, M, can have a maximum of 18 electrons

The arrangement of the periodic table is based on the number and location of electrons such that elements in the 4th row (period 4 elements) have three completed energy levels/rings before, their valence ring making the total number of rings = 4 energy levels/rings.

6 0

3 years ago

How much HCI exists in 275 mL of 0.83 M solution of HCI? Answer in units of mol.

zubka84 [21]

Answer:

0.22825mol HCl

Explanation:

$M=\frac{moles}{liters} \\$

$0.83M HCl = \frac{x(mol)}{0.275L}$

1. Cross multiply!

$\frac{0.83M}{1} =\frac{x}{0.275L}$

$x = 0.22825 mol HCl$

7 0

3 years ago

As an FDA physiologist, you need 0.625 L of phosphoric acid acid / dihydrogen phosphate (H3PO4 (aq) / H2PO4 - (aq) ) buffer with

aksik [14]

Answer:

0.4058L of 1.0M H3PO4

0.2192L of 1.5M NaOH

Explanation:

The pKa of the H3PO4 / H2PO4- buffer is 2.12

To solve this question we must use H-H equation for this system:

pH = pKa + log [H2PO4-] / [H3PO4]

2.75 = 2.12 + log [H2PO4-] / [H3PO4]

0.63 = log [H2PO4-] / [H3PO4]

4.2658 = [H2PO4-] / [H3PO4] (1)

Where [] could be taken as the moles of each reactant

As you have H3PO4 solution, the reaction with NaOH is:

H3PO4 + NaOH → H2PO4- + Na+ + H2O

As you can see, both H3PO4 and H2PO4- comes from the same 1.0M H3PO4 solution

The moles of H3PO4 are:

[H3PO4] = Moles H3PO4 - Moles NaOH

And for H2PO4-:

[H2PO4-] = Moles NaOH added

Replacing in (1):

4.2658 = [Moles NaOH] / [Moles H3PO4 - Moles NaOH]

4.2658 Moles H3PO4 - 4.2658 moles NaOH = Moles NaOH

4.2658 Moles H3PO4 = 5.2658 moles NaOH (1)

In volume:

0.625L = Moles H3PO4 / 1.0M + Moles NaOH / 1.5M

0.625 = Mol H3PO4 + 0.6667 Moles NaOH (2)

Replacing (2) in (1):

4.2658 Moles H3PO4 = 5.2658 (0.625 - Mol H3PO4 / 0.6667)

4.2658 Moles H3PO4 = 5.2658 (0.625 - Mol H3PO4) / 0.6667

4.2658 Moles H3PO4 = 5.2658*(0.9375 - 1.5 mol H3PO4)

4.2658 Moles H3PO4 = 4.9367 -7.8983 mol H3PO4

12.1641 mol H3PO4 = 4.9367

Mol H3PO4 = 0.4058moles * (1L / 1.0moles) =

0.4058L of 1.0M H3PO4

And:

0.625L - 0.4058L =

0.2192L of 1.5M NaOH

5 0

3 years ago