Answer:
The maximum power generated by the circuit is 300 watts.
Step-by-step explanation:
A quadratic function is one that can be written as an equation of the form:
f (x) = ax² + bx + c
where a, b and c (called terms) are any real numbers and a is nonzero.
In this case, f(x) is P(c) [the power generated], x is the current c (in amperes), a = -12, b = 120 and c = 0.
The vertex is a point that is part of the parabola, which has the value as ordered minimum or maximum function. If the scalar a> 0, the parabola opens or faces up and the vertex is the minimum of the function. In contrast, if a <0, the parabola opens downward and the vertex is the maximum of the function.
The calculation of the vertex, which in this case will be the maximum of the function, is carried out as follows:
- The value of x, in this case the value of current c in amperes, can be calculated with the formula
. In this case:
So c= 5 amperes. The current is 5 amperes. - The value of y, in this case the value of the electric current in watts, is obtained by substituting the value of c previously obtained in the function. In this case: P(5)= -12*5²+120*5. So P(5)= 300 watts
<u><em>The maximum power generated by the circuit is 300 watts.</em></u>
Polynomials are equations that uses variables and several terms
The polynomial in standard form is f(x) = x^2 - x -20
<h3>How to determine the polynomial</h3>
The polynomial has 2 zeros.
So, the form of the polynomial is:
f(x) = a(x - x1)(x - x2)
The zeros of the polynomial are 5 and -4.
So, the equation becomes
f(x) = a(x - 5)(x + 4)
The value of a = 1.
So, we have;
f(x) = 1(x - 5)(x + 4)
This gives
f(x) = (x - 5)(x + 4)
Expand
f(x) = x^2 - x -20
Hence, the polynomial in standard form is f(x) = x^2 - x -20
Read more about polynomials at:
brainly.com/question/2833285

if you get a positive value, that means 2 real solutions
if you get 0, means 1 real solution only
if you get a negative value, is an imaginary root solution, same as saying no solution.