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Studentka2010 [4]
3 years ago
11

Thinking about the areas of a Standard Normal Distribution, if a z value is negative, is the area to the left of z less than 0.5

000, greater than 0.5000 or equal to 0.5000?

Mathematics
1 answer:
Dmitrij [34]3 years ago
5 0
A typical plot of the standard normal distribution is shown in the figure below.
The curve is symmetric about z = 0, and the total area under the curve is 1.

It follows that if the value of z is negative, the area to the left of z will be less than 0.5.

Answer:  The area to the left of z is less than 0.5000

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The ratio of buckets of yellow paint to buckets of red paint in the store is 3 to 4. There are 60 buckets of yellow paint. How m
morpeh [17]

Answer:

80 buckets of red paint

Step-by-step explanation:

Given

The ratio of buckets of yellow paint to buckets of red paint in the store to be 3:4

Total ratio = 3 + 4 = 7

Amount of yellow paint = 60

Required

Amount of red paint.

First get the total amount of paint used.

3/7 * x = 60

x is the total paint used

3x/7 = 60

3x = 7*60

x = 420/3

x = 140 buckets of paint

Amount of red paint = Total - Amount of yellow paint

Amount of red paint = 140 - 60

Amount of red paint = 80

Hence there are 80 buckets of red paint in the store

4 0
2 years ago
X has a normal distribution with the given mean and standard deviation. Find the indicated probability. (Round your answer to fo
lapo4ka [179]

Answer:

0.6247

Step-by-step explanation:

The formula for calculating a Z-score is Z = (X - μ)/σ,

where x is the raw score

μ is the population mean

σ is the population standard deviation.

From the question,

μ = 51, σ = 10. We are to find P(36 ≤ X ≤ 56)

Step 1

Find the Probability of X ≤ 36

μ = 51, σ = 10

Z = (X - μ)/σ

Z = 36 - 51/ 10

Z = -15/10

Z = -1.5

We find the Probability of Z = -1.5 from Z-Table

P(X <36) = P(X = 36) = P(Z = -1.5)

= 0.066807

Step 2

Find the Probability of X ≤ 56

μ = 51, σ = 10

Z = (X - μ)/σ

Z = 56 - 51/ 10

Z = 5/10

Z = 0.5

We find the Probability of Z = 0.5 from Z-Table:

P(X < 56) = P(X = 56) = P(Z = 0.5)= 0.69146

Step 3

Find P(36 ≤ X ≤ 56)

P(36 ≤ X ≤ 56) = P(X ≤ 56) - P(X ≤ 36)

= P( Z = 0.5) - P(Z = -1.5)

= 0.69146 - 0.066807

= 0.624653

Approximately to 4 decimal places , P(36 ≤ X ≤ 56) = 0.6247

7 0
3 years ago
I have no idea!! Please help!!!
Ber [7]
The area of a traingle is \frac{1}{2}bh
So we need to know the base and the height
To work out the sides of a right angle triangle we can use a²+b²=c
c is the hypotenuse and a and b are the other sides
Because this triangle is isoceles we know that a and b are the same

a²+b²=c²
a²+a²=c²
2a²=c²
2a²=(x√6)²
2a²=(x√6)(x√6)
2a²=x²+x√6+x√6+6
2a²=x²+x√6+x√6+6
a²=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
a=\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}

A=\frac{1}{2}bh
A=\frac{1}{2}a*a
A=\frac{1}{2}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}
A=\frac{1}{2}×\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
A=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{4}
8 0
2 years ago
I need the answer to this simple Algebra 1 question. Thank you, I will give 10 brainly!!
Finger [1]
The answer is A because 8 is where you started and each time the x number goes up by on the y number goes down by seven (-7)
8 0
3 years ago
Find the area of the shaded regions. Give your answer as a completely simplified exact value in terms of π (no approximations).
olga_2 [115]

Answer:

7\pi cm^2

Step-by-step explanation:

The area of a circle is given by A=\pi r^2

For circle B, the radius is 3 cm, it has an area of \pi *3^2=9\pi cm^2

Circle D also has a radius of 1 cm. Its area is \pi *1^2=\pi cm^2

Circle P also has a radius of 1 cm and area \pi*1^2=\pi cm^2

The area of the shaded region is then 9\pi -\pi-\pi=7\pi cm^2

5 0
3 years ago
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