Answer:
80 buckets of red paint
Step-by-step explanation:
Given
The ratio of buckets of yellow paint to buckets of red paint in the store to be 3:4
Total ratio = 3 + 4 = 7
Amount of yellow paint = 60
Required
Amount of red paint.
First get the total amount of paint used.
3/7 * x = 60
x is the total paint used
3x/7 = 60
3x = 7*60
x = 420/3
x = 140 buckets of paint
Amount of red paint = Total - Amount of yellow paint
Amount of red paint = 140 - 60
Amount of red paint = 80
Hence there are 80 buckets of red paint in the store
Answer:
0.6247
Step-by-step explanation:
The formula for calculating a Z-score is Z = (X - μ)/σ,
where x is the raw score
μ is the population mean
σ is the population standard deviation.
From the question,
μ = 51, σ = 10. We are to find P(36 ≤ X ≤ 56)
Step 1
Find the Probability of X ≤ 36
μ = 51, σ = 10
Z = (X - μ)/σ
Z = 36 - 51/ 10
Z = -15/10
Z = -1.5
We find the Probability of Z = -1.5 from Z-Table
P(X <36) = P(X = 36) = P(Z = -1.5)
= 0.066807
Step 2
Find the Probability of X ≤ 56
μ = 51, σ = 10
Z = (X - μ)/σ
Z = 56 - 51/ 10
Z = 5/10
Z = 0.5
We find the Probability of Z = 0.5 from Z-Table:
P(X < 56) = P(X = 56) = P(Z = 0.5)= 0.69146
Step 3
Find P(36 ≤ X ≤ 56)
P(36 ≤ X ≤ 56) = P(X ≤ 56) - P(X ≤ 36)
= P( Z = 0.5) - P(Z = -1.5)
= 0.69146 - 0.066807
= 0.624653
Approximately to 4 decimal places , P(36 ≤ X ≤ 56) = 0.6247
The area of a traingle is

So we need to know the base and the height
To work out the sides of a right angle triangle we can use a²+b²=c
c is the hypotenuse and a and b are the other sides
Because this triangle is isoceles we know that a and b are the same
a²+b²=c²
a²+a²=c²
2a²=c²
2a²=(x√6)²
2a²=(x√6)(x√6)
2a²=x²+x√6+x√6+6
2a²=x²+x√6+x√6+6
a²=

a=

A=

A=

A=

×

×

A=

×

A=
The answer is A because 8 is where you started and each time the x number goes up by on the y number goes down by seven (-7)
Answer:

Step-by-step explanation:
The area of a circle is given by 
For circle B, the radius is 3 cm, it has an area of 
Circle D also has a radius of 1 cm. Its area is 
Circle P also has a radius of 1 cm and area 
The area of the shaded region is then 