Answer:575 and 1 extra tile
Step-by-step explanation:if the total tiles is 5,176 which will be used in 9 floors .We will divide the total tiles by the floors .Therefore we will get 5176 /9 =575.111
Therefore each floor will have 575 tiles
To get the remaining tiles
575*9 = 5175 which gives us a remainder of 1 tile when you subtract the total 5176 -5175 =1
I’m not to sure because the picture is blurry
50 30 45 that is your answer for this
Answer:
Step-by-step explanation:
![\huge \tan \theta = \frac{15}{8} ...(given) \\ \\ \huge \because \: \cot \theta = \frac{1}{ \tan \theta} \\ \\ \huge \therefore \: \cot \theta = \frac{1}{ \frac{18}{8} } \\ \\ \huge \therefore \: \cot \theta = \frac{8}{15} \\ \\ also \\ \huge \sec \theta = \frac{17}{8} \\](https://tex.z-dn.net/?f=%20%5Chuge%20%5Ctan%20%5Ctheta%20%3D%20%20%5Cfrac%7B15%7D%7B8%7D%20...%28given%29%20%5C%5C%20%20%5C%5C%20%20%5Chuge%20%5Cbecause%20%5C%3A%20%20%5Ccot%20%5Ctheta%20%3D%20%20%5Cfrac%7B1%7D%7B%20%5Ctan%20%5Ctheta%7D%20%5C%5C%20%20%5C%5C%20%20%5Chuge%20%5Ctherefore%20%5C%3A%20%5Ccot%20%5Ctheta%20%3D%20%20%5Cfrac%7B1%7D%7B%20%5Cfrac%7B18%7D%7B8%7D%20%7D%20%5C%5C%20%20%5C%5C%20%20%5Chuge%20%5Ctherefore%20%5C%3A%20%20%5Ccot%20%5Ctheta%20%3D%20%20%5Cfrac%7B8%7D%7B15%7D%20%20%5C%5C%20%20%5C%5C%20also%20%5C%5C%20%5Chuge%20%20%5Csec%20%5Ctheta%20%3D%20%20%5Cfrac%7B17%7D%7B8%7D%20%20%5C%5C%20)
It is number three that is the best i could get