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lorasvet [3.4K]
4 years ago
5

The total weight of George and Tom is 248 lb. If George is 36 lb lighter than Tom, find Tom's weight.

Mathematics
1 answer:
REY [17]4 years ago
4 0
Its 248- 36, come on tommy. 
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zepelin [54]

Answer: if u a math person shouldn't u know how to do it?

Step-by-step explanation:

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4 years ago
Segment CB is a____
Dahasolnce [82]

Answer:

Radius

Step-by-step explanation:

CB = AB/2

Since AB is the diameter, CB is a radius

5 0
3 years ago
Y=1/2x +5<br> Y=-3/2x-7<br> Find x and y
gayaneshka [121]
I'm going to use the substitution method. 

If y = - 3/2 - 7, then:

1/2x + 5 = - 3/2x - 7

Combine like terms: 

4/2x = - 12. Mutiply both sides by 2/4 to get x = -12 (2/4)

Simplify to get:

x = - 6.

Plug - 6 back in for x in either equation.

Y = 1/2( - 6) + 5 which becomes Y = - 3 + 5.

X = - 6, Y = 2





8 0
4 years ago
Kyle received the following course grades for 10​ (three-credit) courses during his freshman​ year:
timofeeve [1]

Answer:

(a) The average grade point is 2.5.

(b) The relative frequency table is show below.

(c) The mean of the relative frequency distribution is 0.3333.

Step-by-step explanation:

The given data set is

4, 4, 4, 3, 3, 3, 1, 1, 1, 1

(a)

The average grade point is

Average=\frac{\sum x}{n}

Average=\frac{4+4+4+3+3+3+1+1+1+1}{10}

Average=2.5

Therefore the average grade point is 2.5.

(b)

\text{Relative frequency}=\frac{\text{Frequency of number}}{\text{Total frequency}}

The relative frequency table is show below:

x                 f                  Relative frequency

4                3                 \frac{3}{10}=0.3

3                3                 \frac{3}{10}=0.3

1                 4                 \frac{4}{10}=0.4

(c)

Mean of the relative frequency distribution is

Average=\frac{0.3+0.3+0.4}{3}

Average=0.3333

Therefore the mean of the relative frequency distribution is 0.3333.

4 0
3 years ago
Tawnee is designing a playground in the shape of a rectangle. If Tawnee increases the length and width of the playground by a sc
svetlana [45]

Answer:

We conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.

Step-by-step explanation:

We know that the perimeter of a rectangle = 2(l+w)

i.e.

P = 2(l+w)

Here

  • 'l' is the length
  • 'w' is the width

Given that the length and width of the playground by a scale factor of 2

A scale factor of 2 means we need to multiply both length and width by 2.

i.e

P = 2× 2(l+w)

P' = 2 (2(l+w))

    = 2P      ∵ P = 2(l+w)

Therefore, we conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.

4 0
3 years ago
Read 2 more answers
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