I xant solve for the value of K

How many pieces of wire 3.6cm long can be cut from a coil of 1m long?What is the length of the piece left over?

sp2606 [1]

Answer:

We can get 27 pieces of wire 3.6 cm long and have a piece 7/9 cm left over

Step-by-step explanation:

Find the "unit length" by dividing 1 m by 3.6 cm:

1 m

-----------

3.6 cm

Recall that 1 m = 100 cm. Multiply the following by the conversion factor 100 cm / 1 m:

1 m 100 cm

----------- * ----------------- = 27,7777777...

3.6 cm 1 m

We can get 27 pieces of wire 3.6 cm long and have a piece 7/9 cm left over (verify this by dividing 7 by 9 on a calculator).

8 0

2 years ago

Read 2 more answers

Solve the system using elimination.<br>3x – 3y = 24<br>2x + 2y = 4<br>The solution is |

LiRa [457]

Answer:

the value of x=5 and y = -3

7 0

3 years ago

Find the average of 8.4 7.5 12.9 and 10.6 also the method how to do it

SashulF [63]

Find the average :8.4+7.5+12.9+10.6 divided by four

8 0

3 years ago

BRAINLIEST TO THE FIRST PERSON TO ANSWER!!The expression on the left side of an equation is shown below.

dusya [7]

Answer:

123added 23

Step-by-step explanation:

4 0

3 years ago

In a list of households, own homes and do not own homes. Five households are randomly selected from these households. Find the p

hichkok12 [17]

Answer:

The probability of success for this case would be:

$p =\frac{9}{15}= 0.6$ representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.6)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X=3)$

And uing the probability mass function we got:

$P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165$

Step-by-step explanation:

Adduming the following info: In a list of 15 households, 9 own homes and 6 do not own homes. Five households are randomly selected from these 15 households. Find the probability that the number of households in these 5 own homes is exactly 3.

Round your answer to four decimal places

P (exactly 3)=

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

The probability of success for this case would be:

$p =\frac{9}{15}= 0.6$ representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.6)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X=3)$

And uing the probability mass function we got:

$P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165$

4 0

3 years ago