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3 years ago

I xant solve for the value of K

Mathematics

1 answer:

exis [7]3 years ago

4 0

K = -3x^2/5 -5x -3 + px/5. I hope that helps.

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More properties of exponets<br> 2y² times 3xy³ over 3x²y^4

Greeley [361]

the answer to the problem is 2y^3 3x3y4+4

6 0

3 years ago

The height, h, in feet of a rock above the ground is given by the equation h = -16t^2 + 24t + 16, where t is the time in seconds

boyakko [2]

The rock will hit the ground at 2 seconds.

Explanation:

Given that the height, h, in feet of a rock above the ground is given by the equation $h=-16t^2+24t+16$ , where t is the time in seconds after the rock is thrown.

We need to determine the time at which the rock will hit the ground.

To determine the time, let us equate the height h = 0 in the equation $h=-16t^2+24t+16$ , we get,

$0=-16t^2+24t+16$

Switch sides, we have,

$-16 t^{2}+24 t+16=0$

Let us solve the equation using the quadratic formula.

Thus, we have,

$t=\frac{-24 \pm \sqrt{24^{2}-4(-16) 16}}{2(-16)}$

Simplifying, we get,

$t=\frac{-24 \pm \sqrt{576+1024}}{-32}$

$t=\frac{-24 \pm \sqrt{1600}}{-32}$

$t=\frac{-24 \pm 40}{-32}$

Hence, the two values of t are

$t=\frac{-24 + 40}{-32}$ and $t=\frac{-24 -40}{-32}$

Simplifying the values, we get,

$t=\frac{16}{-32}$ and $t=\frac{-64}{-32}$

Dividing, we get,

$t=-\frac{1}{2}$ and $t=2$

Since, t cannot negative values, we have,

$t=2$

Thus, the rock will hit the ground at 2 seconds.

8 0

3 years ago

Can someone pls help me with question 7 :(<br> Ignore above text x

cricket20 [7]

Answer: x= 30 because the elevated point is 25 degrees and if you add it with 110 and subtract it with 35 you get 110 + 25 = 135 and 35 - 25 = 15 135 + 15 = 150 and 180 - 150 = 30. so it is 30 degrees. (tell me if i was wrong cause i'm 90% sure this is it but i don't know.)

6 0

3 years ago

Square root of 9/100

timama [110]