The equation of the function in vertex form is y = -(x + 5)² + 4
<h3>What is quadratic equation?</h3>
A quadratic equation is a second-order polynomial equation in a single variable x , ax2+bx+c=0. with a ≠ 0 .
Given that the quadratic function has roots at -3 and -7 and a vertex at (-5,4).
We need to find the equation of the function in vertex form
equation of the function in vertex form.
As per the information given in the question,
The given roots of the function are -3 and -7,
y = a (x + 3) (x + 7)
y = a (x² + 10x + 21)
y = a (x² + 10x + 25 − 4)
y = a (x² + 10x + 25) − 4a
y = a (x + 5)² − 4a
The vertex is (-5, 4),
So, a = -1.
y = -(x + 5)² + 4
Hence, y = -(x + 5)² + 4 is the equation of the function in vertex form
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Answer:
Wouldn't it just be 8?
Step-by-step explanation:
f(8)
8f^1-1
8f^0
8x1
8
............You lost $130......................
9514 1404 393
Answer:
Step-by-step explanation:
If the square starts as n rows of n columns, adding another row of n columns will make a rectangle with dimensions n+1 rows by n columns.
__
The total number of tiles in the rectangle is said to be ...
n(n+1) = 2256
n^2 +n +1/4 = 2256 1/4 . . . complete the square
(n +1/2)^2 = (47 1/2)^2 . . . . rewrite as squares
n = 47
Answer:
Its b
Step-by-step explanation:
5x 12= 60
60 - 20= 40
3x 12= 36
36+4 = 40