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kobusy [5.1K]
3 years ago
14

Four consecutive odd integers add up to -48. What is the least of these integers?

Mathematics
1 answer:
Semmy [17]3 years ago
3 0

Answer:

-9

Step-by-step explanation:

Four consecutive odd integers be (2x - 3),(2x -1),(2x + 1),(2x + 3)

2x-3 + 2x - 1 +2x+1 + 2x+3 = -48

2x + 2x + 2x +2x - 3 - 1 + 3 + 1 = -48

8x = -48

x = -48/8

x = -6

Least of these integer = 2x + 3 = 2*(-6) + 3 = -12 + 3 = -9

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a. median is 8

b. first quartile is 7

c. third quartile is 9.5

d. below

e. below

Step-by-step explanation:

7, 10, 10, 6, 7, 8, 8, 7, 9.

Place number in order least to greatest

6, 7, 7, 7, 8, 8, 9, 10, 10

a. What is the median?

The median is the middle number in a data set

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9 + 1 / 2 = 10 / 2

<u>6, 7, 7, 7,</u> 8, <u>8, 9, 10, 10</u>

The median is 8

b. What is the first quartile?

Q1 is the central point between the smallest score and the median

<u>6,</u> 7, 7<u>, 7 </u>

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c. What is the third quartile?

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<u>8</u>, 9, 10, <u>10</u>

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9 + 10 / 2 = 19 / 2 = 9.5

d. Draw a box plot of the data.

below

e. Write two conclusions about the data shown in the box plot.

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2 years ago
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