Please, share just ONE problem at a time. Thanks.
<span>Solve 2x^2-12x+20=0:
Simplify this by dividing each term by 2: x^2 - 6x + 10 = 0
Identify a, b and c: a=1, b=-6 and c=10. Then b^2=36.
Write out the solutions using the quadratic formula:
6 plus or minus sqrt(36-40)
x = ---------------------------------------
2
sqrt(36-40) = sqrt(-4) = plus or minus i2
Then:
6 plus or minus i2
x = --------------------------- (answer)
2</span>
its 1200 i think i work it out but i could have done it wrong
1.168 rounded off to nearest thousands = 1168
