Look at pic for question and answer choices.

If f(x)=5x, what is f^-1(x)?

Georgia [21]

Answer:

first thing to do is get up from your sit and go cry because that question is to hard

5 0

4 years ago

IS A PICTURE!!!! thank you for your time

yaroslaw [1]

Answer:

I am not sure, but I think you would check for the side with the longest length(hypothenuse) and check if the formula of a^2+b^2=c^2(side with the longest length) satisfies it.

3 0

3 years ago

The sum of 2 numbers is 22. 2 times the first number is 10 times the second. what are the numbers

gogolik [260]

Answer:

Step-by-step explanation:

Set the two unknown numbers to X and Y.

X + Y = 22

2X = 10Y

Rewrite the second equation as: X = 5Y

Now use this in the first equation: 6Y=22

Y = 3.67 [3 2/3]

X = 18.33 [18 1/3]

---------------------------------------

3 2/3 + 18 1/3 = 22, and

2*(18 1/3) = 10*(3 2/3)

5 0

3 years ago

An airplane makes a 400-mile trip against a head wind in 4 hours. The return trip takes 2.5 hours, the wind now being a tall win

tangare [24]

Answer:

$v_p=130\ miles/h$

$v_w=30\ miles/h$

Step-by-step explanation:

Lets call $v_p$ the the still-air speed of the plane and $v_w$ the speed of the wind. On the first part the speed of the plane relative to the ground will be $v_1=v_p-v_w$ , and on the second part it will be $v_2=v_p+v_w$ .

We know that the distance d=400 miles on the first and second parts are the same, so by the definition of velocity we will have:

$v_1=\frac{d}{t1}$

$v_2=\frac{d}{t2}$

Or:

$v_p-v_w=\frac{d}{t1}$

$v_p+v_w=\frac{d}{t2}$

Adding both equations:

$(v_p-v_w)+(v_p+v_w)=2v_p=\frac{d}{t1}+\frac{d}{t2}$

$v_p=\frac{1}{2}(\frac{d}{t1}+\frac{d}{t2})$

Which for our values is:

$v_p=\frac{1}{2}(\frac{400\ miles}{4h}+\frac{400\ miles}{2.5h})=130\ miles/h$

If instead of adding, we substact, we would have:

$(v_p+v_w)-(v_p-v_w)=2v_w=\frac{d}{t2}-\frac{d}{t1}$

$v_w=\frac{1}{2}(\frac{d}{t2}-\frac{d}{t1})$

Which for our values is:

$v_w=\frac{1}{2}(\frac{400\ miles}{2.5h}-\frac{400\ miles}{4h})=30\ miles/h$

6 0

4 years ago

In a group of 65 students when you have brown eyes and 30 have blue eyes. Find the Probability that a student pick from this gro

Gemiola [76]

Answer:

The probability that a student pick from this group at random either has blue or brown eyes is

P = 40/65 = 0.6154

P = 61.54%

Corrected question;

In a group of 65 students 10 have brown eyes and 30 have blue eyes. Find the Probability that a student pick from this group at random either has blue or brown eyes

Step-by-step explanation:

Given;

Total number of students = 65

Number of students with either blue or brown eyes;

= 10+30 = 40

The probability that a student pick from this group at random either has blue or brown eyes is

P = 40/65 = 0.6154

P = 61.54%

4 0

3 years ago