Answer:
Step-by-step explanation:
Given tq equation of the height reached by the rocket as y=-16x^2+235x+133
The velocity of the object at its maximum height is zero
v = dy/dx = 0(at max height)
v =-32x +235
0 =-32x+235
x = 235/32
x = 7.34
Hence the rocket will reach its maximum height after 7.34seconds
Answer:
C; right answer on Khan Academy
Step-by-step explanation:
I think... J because
x + 1 / x^3 - x
Factor out x from the expression
x + 1 / xx(x^2 - 1)
Use a^2 - b^2 = (a - b)(a + b) to factor the expression
x + 1 / x • (x - 1) • (x + 1)
Reduce the fraction with x+ 1
1 / x • (x - 1)
Distribute x through the parentheses
1 / x^2 - x
:)
Answer:
<h3>The answer is </h3><h3 /><h3>1125 Kg</h3>
Step-by-step explanation:
To find the mass in kg we must first convert the density from g/cm³ to kg/m³
That's 7.5 g/cm³ = 7500kg/m³
Density = mass / volume
Volume of block = 1.5 × 0.4 × 0.25
= 0.15m³
mass = Density × volume
= 7500 × 0.15
<h3>= 1125 Kg</h3>
Hope this helps you
