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Gnom [1K]
3 years ago
8

Adding and subtracting what is the solution to x = 4 = 12

Mathematics
1 answer:
marshall27 [118]3 years ago
8 0
The answer would be 3 because 3✖️4= 12
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Does someone know how to solve this problem?
Naddika [18.5K]

Answer:

Acute scalene triangle.

Step-by-step explanation:

Acute scalene triangle.

Sides: a = 4   b = 7   c = 8

Area: T = 13.998

Perimeter: p = 19

Semiperimeter: s = 9.5

Angle ∠ A = α = 29.995° = 29°59'41″ = 0.524 rad

Angle ∠ B = β = 61.028° = 61°1'42″ = 1.065 rad

Angle ∠ C = γ = 88.977° = 88°58'37″ = 1.553 rad

Height: ha = 6.999

Height: hb = 3.999

Height: hc = 3.499

Median: ma = 7.246

Median: mb = 5.268

Median: mc = 4.062

Inradius: r = 1.473

Circumradius: R = 4.001

Vertex coordinates: A[8; 0] B[0; 0] C[1.938; 3.499]

Centroid: CG[3.313; 1.166]

Coordinates of the circumscribed circle: U[4; 0.071]

Coordinates of the inscribed circle: I[2.5; 1.473]

Exterior (or external, outer) angles of the triangle:

∠ A' = α' = 150.005° = 150°19″ = 0.524 rad

∠ B' = β' = 118.972° = 118°58'18″ = 1.065 rad

∠ C' = γ' = 91.023° = 91°1'23″ = 1.553 rad

7 0
3 years ago
And
kramer

Answer:

can you send a picture please so i can see it?

5 0
2 years ago
Which equation is a point slope form equation for line AB ?
kolezko [41]
I think the answer is A
5 0
3 years ago
Read 2 more answers
2.
abruzzese [7]

Answer:

  a) 30 kangaroos in 2030

  b) decreasing 8% per year

  c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo

Step-by-step explanation:

We assume your equation is supposed to be ...

  P(t) = 76(0.92^t)

__

a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30

In the year 2030, the population of kangaroos in the province is modeled to be 30.

__

b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.

The population is decreasing by 8% each year.

__

c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.

  P(100) = 75(0.92^100) = 76(0.0002392)

  P(100) ≈ 0.0182, about 1/55th of a kangaroo

5 0
3 years ago
Hawaii 0.288% = what fraction
Sindrei [870]

Answer:

36⁄125 or if we are talking about the lowest term it is 9 /3125


Step-by-step explanation:

Step 1: 0.288 = 288⁄1000  

Step 2: Simplify 288⁄1000 = 36⁄125 Percent" or "%" means "out of 100" or "per 100",



<em>Or for the lowest term:</em>

Therefore 0.288% can be written as  

0.288

100

.

Next, we can multiply by  

1

in the form of  

1000

1000

to eliminate the decimal in the numerator:

1000

1000

×

0.288

100

⇒

1000

×

0.288

1000

×

100

⇒

288

100000

.

We can now reduce the fraction as:

288

100000

⇒

32

×

9

32

×

3125

⇒

32

×

9

32

×

3125

⇒

9

3125

.

4 0
2 years ago
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