Answer:
Acute scalene triangle.
Step-by-step explanation:
Acute scalene triangle.
Sides: a = 4 b = 7 c = 8
Area: T = 13.998
Perimeter: p = 19
Semiperimeter: s = 9.5
Angle ∠ A = α = 29.995° = 29°59'41″ = 0.524 rad
Angle ∠ B = β = 61.028° = 61°1'42″ = 1.065 rad
Angle ∠ C = γ = 88.977° = 88°58'37″ = 1.553 rad
Height: ha = 6.999
Height: hb = 3.999
Height: hc = 3.499
Median: ma = 7.246
Median: mb = 5.268
Median: mc = 4.062
Inradius: r = 1.473
Circumradius: R = 4.001
Vertex coordinates: A[8; 0] B[0; 0] C[1.938; 3.499]
Centroid: CG[3.313; 1.166]
Coordinates of the circumscribed circle: U[4; 0.071]
Coordinates of the inscribed circle: I[2.5; 1.473]
Exterior (or external, outer) angles of the triangle:
∠ A' = α' = 150.005° = 150°19″ = 0.524 rad
∠ B' = β' = 118.972° = 118°58'18″ = 1.065 rad
∠ C' = γ' = 91.023° = 91°1'23″ = 1.553 rad
Answer:
can you send a picture please so i can see it?
Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
__
a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
__
b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
__
c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo
Answer:
36⁄125 or if we are talking about the lowest term it is 9
/3125
Step-by-step explanation:
Step 1: 0.288 = 288⁄1000
Step 2: Simplify 288⁄1000 = 36⁄125 Percent" or "%" means "out of 100" or "per 100",
<em>Or for the lowest term:</em>
Therefore 0.288% can be written as
0.288
100
.
Next, we can multiply by
1
in the form of
1000
1000
to eliminate the decimal in the numerator:
1000
1000
×
0.288
100
⇒
1000
×
0.288
1000
×
100
⇒
288
100000
.
We can now reduce the fraction as:
288
100000
⇒
32
×
9
32
×
3125
⇒
32
×
9
32
×
3125
⇒
9
3125
.
