The estimate of the population proportion of defectives is 0.05.
Given that,
There are 10 different samples of 50 observations, that is, total of 500 observations.
To find : The estimate of the population proportion of defectives
And total number of defectives from 500 observations is (5+1+1+2+3+3+1+4+2+3) = 25
Thus, the point estimate for the population proportion defectives will be,
=25/500=0.05
or just obtain the individual proportion of each sample and then take their average to obtain the same result.
Thus, the point estimate for the population proportion defectives will be 0.05
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Answer:
Step-by-step explanation:
Given that a box contains 45 light bulbs, of which 36 are good and the other 9 are defective.
Probability for any one to be defective as of now is 
a) 
b) After I draw we have 35 good ones and 9 defective
P(F/E) =
c) P(G/EF)
This is the probability for iii bulb to be good given I and II are goog.
Once I and ii are good we have 43 bulbs with 34 good ones

Percent means parts out of 100
105%=105/100=1.05
'of' means multiply
105% of 260=1.05 times 260=273
Answer:

Step-by-step explanation:
