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patriot [66]
3 years ago
6

Veri made $25 babysitting.if she makes $8 an hour,how many hours did she babysit?

Mathematics
1 answer:
taurus [48]3 years ago
8 0
3.12 I got the answer by dividing 25 by 8
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If the concentration of mercury in the water of a polluted lake is 0.300 μg (micrograms) per liter of water, what is the total m
Reika [66]

Answer: 151.305 kg

Step-by-step explanation:

0.300μg = 0.3x10⁻⁶ g/l

mass in kg?

Volume of lake = surface area * depth

surface area = 13mi²

depth = 49 ft

<u>Feet to miles</u>

49 ft → mi = 0.00928 mi

(1 mi = 5280 ft)

V = 13*0.00928 = 0.121 mi³

<u>cubic Miles to cubic meters</u>

1mi³ = 4168182000 m³

0.121 mi³ = 504350022 m³

<u>Cubic meters to liters</u>

1L = 1000 m³

Lake has 5.04350022x10¹¹ L

Concentration = 0.3x10⁻⁶ g/l

Lake has 151305 g of Hg = 151.305 kg of Hg

6 0
3 years ago
What’s the lcm of 24 &amp;8 ?
LenaWriter [7]
The answer is 24 The multiples of 8 is 8 16 24..... the multiples of 24 48 72..... so therefore the answer is 24 make me the brainest
6 0
3 years ago
Which equation represents a proportional relationship between x and y values
Troyanec [42]
Remember this! The equation that represents a proportional relationship, or a line, is y=kx, where k is the constant of proportionality.
4 0
3 years ago
Wich equation can help you estimate the difference of 63,412 and 31,500
Harrizon [31]

Answer:

63000- 32000

Step-by-step explanation:

its 400 so it rounds down and 500 rounds up

4 0
3 years ago
Suppose that the functions g and f are defined as follows.
Sholpan [36]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Given:

\to g(x)= -3+2x^2 \\\\\to f(x)=9-6x

Calculating the value of (\frac{g}{f})(2):

\to (\frac{g}{f}) (2)= (\frac{g(x)}{f(x)}) \times  (2)

               =\frac{2x^2-3}{9-6x} \times 2\\\\=\frac{2\cdot 2^2-3}{3(3-2\cdot 2)} \\\\=\frac{2\cdot 4-3}{3(-1)}\\\\ =\frac{8-3}{-3}\\\\  =\frac{5}{-3}\\\\  = - \frac{5}{3}\\\\

x=- \frac{\sqrt{3}}{2} and x=\frac{\sqrt{3}}{2} are not in the domain.

Domain: x \belong (- \infty, -\frac{\sqrt{3}}{2})\cup (- \frac{\sqrt{3}}{2},  \frac{\sqrt{3}}{2} )\cup (\frac{\sqrt{3}}{2}, \infty)

8 0
3 years ago
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