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vekshin1
3 years ago
8

3/z when z=2 SORRY FOR HAVING 2 QUESTIONS IN A ROW

Mathematics
2 answers:
bearhunter [10]3 years ago
8 0

Answer:

3/z\: when\:z=2

\frac{3}{z}=2

\frac{3}{z}z=2z

2z=3

\frac{2z}{2}=\frac{3}{2}=z=\frac{3}{2}

z=1.5\right

<u>OAmalOHopeO</u>

8090 [49]3 years ago
4 0

3/z when z = 2

= 3/2

= 1.5

This is the answer

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justin has 7.50 more than eva and emma has 12 less than justin. together, they have a total of 63.00. how much does each person
lina2011 [118]
1st statement
Justin has 7.5 more than Eva        7.5+E
Eva = E
2nd statement
Emma has 12 less than Justin         J - 12
when J= Justin = 7.5 + E
last statement
Eva+Justin+Emma = 63
E + (7.5+E) + (7.5+E-12) =63
ADD UP
3E + 15 - 12 = 63
3E + 3 = 63
3E=63 - 3
3E=60
E=20 EMMA receives 20
J=7.5+20
J=27.5  JUSTIN receives 27.5
M=J-12
M=27.5-12
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8 0
3 years ago
Read 2 more answers
A delivery truck can transport packages weighing at most 3,800 pounds(lbs) and with a volume of no more than 400 cubic feet (ft^
Makovka662 [10]
Let's approach this problem by slowly eliminating choices.

First consider the keyword "at most" and "no more than". This means that the inequality should be less than or equal to the constant value stated. This will automatically eliminate two choices with the greater than symbol favoring the variables - choices A and D.

Next we associate the right constants to the right coefficients of variables. The two kinds of weight the truck transports are 30 and 65 lbs, and we know that this should not exceed 3,800 lbs. This is therefore our first inequality. The other inequality is for the volume. The combinations of the two volumes 4 and 9 cubic feet should not exceed 400 cubic feet when transported.

If you try to construct the inequality and miss it among the choices, don't worry! Let's try doing some simplifications first and see if it matches either B or C.

After simplification you can get 6x+13y \leq 760 from dividing the equation by 5 and 4x+9y \leq 400 for leaving it as it is.

Looking carefully, we can see that this is equivalent to option B.

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4 years ago
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V125BC [204]

Given that

log (x+y)/5 =( 1/2) {log x+logy}

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log a+ log b = log ab

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We know that log a^m = m log a

⇛log (x+y)/5 = log (xy)^1/2

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⇛(x+y)/5 = √(xy)

On squaring both sides then

⇛{ (x+y)/5}^2 = {√(xy)}^2

⇛(x+y)^2/5^2 = xy

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Over [174]

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