Use subtraction to find the lengths of segments WX and XY.
Point W is on (9,3), point X is on (5,3) and point Y is on (5,9), if I'm reading this correctly.
Point W and point X match with their y-values, so we ignore them. Subtract the x-values, 9 and 5, to get the length. In this case, the length is 4 units.
Point X and point Y match with their x-values, so we ignore them. Subtract the y-values, 3 and 9, to get 6.
Since the problem is asking for length, you always subtract the smaller number from the larger one, as you can't have a negative distance or length.
Rhombus or diamond I think. I hope that this helps!
Answer:
Step-by-step explanation:
We have the equations
4x + 3y = 18 where x = the side of the square and y = the side of the triangle
For the areas:
A = x^2 + √3y/2* y/2
A = x^2 + √3y^2/4
From the first equation x = (18 - 3y)/4
So substituting in the area equation:
A = [ (18 - 3y)/4]^2 + √3y^2/4
A = (18 - 3y)^2 / 16 + √3y^2/4
Now for maximum / minimum area the derivative = 0 so we have
A' = 1/16 * 2(18 - 3y) * -3 + 1/4 * 2√3 y = 0
-3/8 (18 - 3y) + √3 y /2 = 0
-27/4 + 9y/8 + √3y /2 = 0
-54 + 9y + 4√3y = 0
y = 54 / 15.93
= 3.39 metres
So x = (18-3(3.39) / 4 = 1.96.
This is a minimum value for x.
So the total length of wire the square for minimum total area is 4 * 1.96
= 7.84 m
There is no maximum area as the equation for the total area is a quadratic with a positive leading coefficient.
Answer:
The Answer is: y = -2/3x + 10/3
Step-by-step explanation:
Given points (-1, 4) and (8, -2) first find the slope:
m = (y - y1)/(x - x1)
m = (4 - (-2)) / (-1 - 8)
m = 4 + 2 / -9
m = -6/9 = -2/3
Use the point slope form and point (8, -2) and slove for y:
y - y1 = m(x - x1)
y - (-2) = -2/3(x - 8)
y + 2 = -2/3x + 16/3
y = -2/3x + 16/3 - 2
y = -2/3x + 16/3 - 6/3
y = -2/3x + 10/3
Proof using the point (-1, 4):
f(-1) = -2/3(-1) + 10/3
= 2/3 + 10/3
= 12/3 = 4, giving point (-1, 4)
Hope this helps! Have an Awesome Day!! :-)
Answer:
If the complement of an angle is 25 degrees, then the measurement of the angle will be 65 degrees.
