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lianna [129]
3 years ago
5

Please help!! Find the number if intercepts of the graph of the function f(x)=x^2-2x+5​

Mathematics
1 answer:
hodyreva [135]3 years ago
7 0

Answer: X does not intercept (none)                                                                                      

Y=(0,5)

Step-by-step explanation:

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How is the function shown below related to y=x? Graph the function by translating the parent function y=x+5
AveGali [126]

Consider x=0.

The output of the function y=x is y=0.

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The value 5 is not 5 less than 0, not 1/5 of 0, and not 5 times 0. Rather, it is 5 more than 0, corresponding to selection ...

... C. Each output of y=x+5 is 5 more than the corresponding output of y=x.

7 0
3 years ago
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Graph the inequality. 3x+4y>20
gogolik [260]

Answer:

y=-3/4x+5

Step-by-step explanation:

3x+4y>20

4y>-3x+20

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Answer:

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8 0
3 years ago
What is the equation of this line in standard form? 8x−7y=−25 8x−9y=23 8x−9y=−23 9x−8y=23 Number graph ranging from negative fiv
Gnoma [55]

Answer:

The equation of line is:

8x-9y=-23

Step-by-step explanation:

We are given that a graph is  a that passes through two points:

(-4,-1) and (\dfrac{1}{2},3)

We know that the equation of line passing through two points:

(a,b) and (c,d) is given by:

y-b=\dfrac{d-b}{b-a}\times (x-a)

Here we have:

(a,b)=(-4,-1) and (c,d)=(\dfrac{1}{2},3)

Hence, the equation of line is:

y-(-1)=\dfrac{3-(-1)}{\dfrac{1}{2}-(-4)}\times (x-(-4))\\\\y+1=\dfrac{3+1}{\dfrac{1}{2}+4}\times (x+4)\\\\y+1=\dfrac{4}{\dfrac{9}{2}}\times (x+4)\\\\y+1=\dfrac{4\times 2}{9}\times (x+4)\\\\y+1=\dfrac{8}{9}\times (x+4)\\\\9\times (y+1)=8\times (x+4)\\\\9y+9=8x+8\times 4\\\\9y+9=8x+32\\\\8x-9y=9-32\\\\8x-9y=-23

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8x-9y=-23

5 0
2 years ago
What is the exponential function modeled by the following table?
Ierofanga [76]
\bf \begin{array}{ccll}
x&f(x)\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
2&\stackrel{3^2+1}{10}\\
3&\stackrel{3^3+1}{28}\\
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\end{array}\implies f(x)=3^x+1
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