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2 years ago

The range of f(x) = |x| is y ≥ 0. If a < 0 and b ≠ 0 for g(x) = a|x| + b, what is the range of function g?

Mathematics

1 answer:

kifflom [539]2 years ago

3 0

Answer:

blue or maybe green try purple

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A toaster has four slots for bread. Once the toaster is warmed up, it takes 35 seconds to make 4 slices of toast, 70 seconds to

soldier1979 [14.2K]

Answer:

192.5

Step-by-step explanation:

You are adding 35 sec to every 4 pieces of bread once you get to 20 you divide 35 and get 17.5 so the answer id 192.5

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

Prove that sin²∅+cos²∅=1 ?

sasho [114]

Step-by-step explanation:

Let ABC be a right angled triangle where there's a right angle in B . Let the measure of the angle BAC be ∅. So,

$\sin(∅) = \frac{BC}{AC}$

$= > {\sin}^{2}∅ = \frac{ {BC}^{2} }{ {AC}^{2} }$

Also,

$\cos(∅) = \frac{AB}{AC}$

$= > { \cos}^{2}∅ = \frac{ {AB}^{2} }{ {AC}^{2} }$

Now adding the values of sin^2∅& cos^2∅,

${ \sin}^{2} ∅ + { \cos}^{2} ∅ = \frac{ {BC}^{2} }{ {AC}^{2} } + \frac{ {AB}^{2} }{ {AC}^{2} }$

$= > { \sin}^{2} ∅ + { \cos}^{2} ∅ = \frac{ {AB}^{2} + {BC}^{2} }{ {AC}^{2} }$

But we know that

${AC}^{2} = {AB}^{2} + {BC}^{2}$ by applying Pythagorean Theorem

So ,

$= > { \sin}^{2} ∅ + { \cos}^{2} ∅ = \frac{ {AC}^{2} }{ {AC}^{2} } = 1$

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2 years ago

Reily adds 45.3 and 3.21.should his sum be greater than or less than 48?Tell how you know.

Eddi Din [679]

Greater than 48, because just taking whole numbers 45 + 3 = 48 already.

45.3 is greater than 45 and 3.21 is greater than 3

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3 years ago

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4) How many 65 dollar pairs of shoes can you buy with $1,365?

Luden [163]

The answer to this division question is 21

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3 years ago

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