Answer:
45
Step-by-step explanation:
plug in 3 where the xs are
2(3)(6(3)-5(3))+(3)^2(5(3)-4(3)=45
2(3)=6
6(3)=18
-5(3)=15
(3)^2=9
5(3)=15
-4(3)=-12
Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)
J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)
K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)
L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)
M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)
3x^2 + 21x
Is the answer without a doubt.
Answer:
12(3+5)
Step-by-step explanation:
The greatest common factor is 12
12*3 + 12*5
12(3+5)
