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Marrrta [24]
2 years ago
8

If fx = 5x - what is the value of f(5)?

Mathematics
1 answer:
ra1l [238]2 years ago
3 0

Answer:

25

Step-by-step explanation:

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Jenny and Natalie are selling cheesecakes for a school fundraiser. Customers can buy chocolate cakes and vanilla cakes. Jenny so
IrinaVladis [17]

The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

<em><u>Solution:</u></em>

Let "c" be the cost of 1 chocolate cake

Let "v" be the cost of 1 vanilla cake

<em><u>Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars</u></em>

Therefore, we can frame a equation as:

14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

14 \times c + 5 \times v=119

14c + 5v = 119 ------- eqn 1

<em><u>Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars</u></em>

Therefore, we can frame a equation as:

10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

10 \times c + 10 \times v = 130

10c + 10v = 130 -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

28c + 10v = 238 ------ eqn 3

<em><u>Subtract eqn 2 from eqn 3</u></em>

28c + 10v = 238

10c + 10v = 130

( - ) --------------------------

18c = 108

c = 6

<em><u>Substitute c = 6 in eqn 1</u></em>

14(6) + 5v = 119

84 + 5v = 119

5v = 119 - 84

5v = 35

v = 7

Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

8 0
2 years ago
Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [
Darya [45]

Answer:

<em>A=3 and B=6</em>

Step-by-step explanation:

<u>Increasing and Decreasing Intervals of Functions</u>

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9

Computing the first derivative:

f' ( x ) = - 6 x^3 + 54 x - 108

We find the critical points equating f'(x) to zero

- 6 x^3 + 54 x - 108=0

Simplifying by -6

x^2 -9 x +18=0

We get the critical points

x=3,\ x=6

They define the following intervals

(-\infty,3),\ (3,6),\ (6,+\infty)

Thus A=3 and B=6

3 0
3 years ago
I WILL GIVE BRAINLIST HELP PLEASE
il63 [147K]

Answer:

area- 55 perimeter - 24

Step-by-step explanation:

small rectangle =

5- 3 = 2

2 × 3 = 6cm²

big rectangle =

4 + 3 = 7

7 × 7 = 49cm²

All together

6 + 49 = 55cm²

Perimeter -

7 0
3 years ago
123÷6×7[(654+2)×(12÷3)]
melomori [17]

Answer:

Step-by-step explanation:

123/6 x 7[(654 + 2) x (12/3)].....do whats in parenthesis first

123/6 x 7[656 x 4] ......do whats in brackets

123/6 x 7(2624) ....do multiplication/division from left to right, whichever comes first

20.5 x 18,368 =

376544 <===

8 0
3 years ago
Read 2 more answers
SOMEONE PLS HELP WILL GIVE BRAINLIEST ANSWER IF CORRECT
Mamont248 [21]
Complementary angles add up to 90°
and supplementary angles add up to 180°

Add the two angles together
82+98=180
So the measure of these two angles are supplementary
6 0
3 years ago
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