Let's start by assuming Armando's house is between Joey's and the park.
Let

be the distance Joey walked to Armando's house.
<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.
</span>


That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)
Let

be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like

Let's get rid of the plus/minuses. Squaring,



For us, that's a quadratic equation for


I'll skip right to the solutions,


We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.
Answer:
A
Step-by-step explanation:
Answer:
D) v = -2,000y + 20,000.
Step-by-step explanation:
The question gives a linear relationship between two quantities. This means that the relationship between the initial value of the car and the amount it depreciates each year is proportional, or constant. Since the value of the car decreases by 10% of its initial value each year, then each year the value will decrease by 10% of 20,000 or 0.10 x 20000 = $2,000. Since we know the value is decreasing each year, this amount would be subtracted from the initial value of $20,000. So, D) v = -2,000y + 20,000 would be the only equation that represents this scenario.