4n/4n-4 × n-1/n+1
= 4n(n-1)/(4n-4)(n+1)
= (4n^2 - 4n)/(4n^2 + 4n - 4n-4)
= (4n^2 - 4n)/(4n^2 - 4)
= 4(n^2 - n)/4(n^2 - 1)
=(n^2 - n)/(n^2 - 1)
Because of the vertical asymptote and the change in concavity, we conclude that the correct option is B.
<h3>
Which is the graph of cotangent of x?</h3>
Remember that cot(x) = 1/tan(x).
Then we can rewrite:
cot(x) = cos(x)/sin(x).
We know that for x = 0, we have:
cot(0) = cos(0)/sin(0) = 1/0
Then we have a vertical asymptote that tends to ± infinity.
The only graph that meets this condition is the second and the third one, and by the curvature (we need to have a change of concavity/convexity) in the tangent function.
From that, we conclude that the correct option is B.
If you want to learn more about trigonometric functions:
brainly.com/question/8120556
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F = 30
g = 15
Yeah, hope this helps, etc.
Answer: 11
Step-by-step explanation: The factors of 88 are 1,2,4,8,11,22,44,88; The factors of 121 are 1,11,121.
