Question

Remove parameter y=bsintheta x=bsectheta

Answer 1

$\bf \begin{cases} y=bsin(\theta)\\\\ x=bsec(\theta)\implies \frac{x}{sec(\theta)}=\boxed{b}\\ ----------\\ y=\boxed{\frac{x}{sec(\theta)}}sin(\theta) \end{cases} \\\\\\ \textit{and you can simplify it further if you want} \\\\\\ y=\cfrac{xsin(\theta)}{\frac{1}{cos(\theta)}}\implies y=\cfrac{xsin(\theta)}{1}\cdot \cfrac{cos(\theta)}{1}\implies y=xsin(\theta)cos(\theta)$