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3 years ago

Remove parameter y=bsintheta x=bsectheta

1 answer:

8 0

$\bf \begin{cases}
y=bsin(\theta)\\\\
x=bsec(\theta)\implies \frac{x}{sec(\theta)}=\boxed{b}\\
----------\\
y=\boxed{\frac{x}{sec(\theta)}}sin(\theta)
\end{cases}
\\\\\\
\textit{and you can simplify it further if you want}
\\\\\\

y=\cfrac{xsin(\theta)}{\frac{1}{cos(\theta)}}\implies y=\cfrac{xsin(\theta)}{1}\cdot \cfrac{cos(\theta)}{1}\implies y=xsin(\theta)cos(\theta)$

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You want to be able to withdraw $25,000 from your account each year for 20 years after you retire.

Nina [5.8K]

Answer:

When using formulas in application, or memorizing them for tests, it is helpful to note the similarities and differences in the formulas so you don’t mix them up. Compare the formulas for savings annuities vs payout annuities.

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3 0

3 years ago

You are playing a new video game. The table shows the proportional relationship between the number of levels completed and the t

Lana71 [14]

The time to complete 2 levels is (c) 60 minutes

<h3>How to determine the time to complete 2 levels?</h3>

The table of values is given as

Number of Levels Time (hours)

2 ?

3 1.5

Express the blank (?) with y

Number of Levels Time (hours)

2 y

3 1.5

The ordered pairs from the table are

(x, y) = (2, y) and (3, 15)

The table shows the proportional relationship

This means that the equation can be represented as

y = Y/X * x

Where

(x, y) = (2, y)

(X, Y) = (3, 1.5)

So, we have

y = 1.5/3 * 2

Evaluate the quotient

y = 0.5 * 2

This gives

y = 1 hour

Convert to minutes

y = 60 minutes

Hence, the time is 60 minutes

Read more about linear equation at

brainly.com/question/13738662

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7 0

1 year ago

I need help <br>what is the answer

Masja [62]

The answer:
It is B.8

6 0

3 years ago

Read 2 more answers

Micheal is 5 years older than Rui Feng and Vishal is thrice as old as Micheal if Rui Feng is p years old, find i) Michael's pres

Kitty [74]

Answer:

Michael's present age = p + 5

Michael's present age = 3p + 15

Sum of there ages 6 year age = 5p + 38

Sum of there ages 3 year ago = 5p - 11

Step-by-step explanation:

Assume;

Age of Rui Feng = x

Age of Micheal = x + 5

Age if Vishal = 3[x+5]

Given:

Age of Rui Feng = P

Computation:

Michael's present age = Age of Rui Feng + 5

Michael's present age = p + 5

Vishal's present age = 3[p + 5]

Michael's present age = 3p + 15

Sum of there ages 6 year age = [p + 6] + [p + 5 + 6] + 3[p + 5] + 6

Sum of there ages 6 year age = 5p + 38

Sum of there ages 3 year ago = [p - 3] + [p + 5 - 3] + 3[p + 5] - 3

Sum of there ages 3 year ago = 5p - 11

8 0

3 years ago

A certain bookstore chain has two stores, one in San Francisco and one in Los Angeles. It stocks three kinds of books: hardcover

riadik2000 [5.3K]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

$\left[\begin{array}{cccc}T&H&S&P\\S&600&1300&2000\\L&400&300&400\end{array}\right]$ = A.

In the above matrix A, the columns refers the three type of books and the rows refers the from which stores the books are been sold.

The numbers represents the corresponding sales in the month of January.

The sale is same for the 6 months.

Hence, 6A = $\left[\begin{array}{cccc}T&H&S&P\\S&3600&7800&12000\\L&2400&1800&2400\end{array}\right]$ . This matrix 6A represents the total sales over the 6 months.

(b)

If we denote the books in stock at the starting of January by B, then

B = $\left[\begin{array}{cccc}T&H&S&P\\S&1000&3000&6000\\L&1000&6000&3000\end{array}\right]$ .

Each month, the chain restocked the stores from its warehouse by shipping 500 hardcover, 1,400 softcover, and 1,400 plastic books to San Francisco and 500 hardcover, 500 softcover, and 500 plastic books to Los Angeles.

If we represent the amount restocked books at the end of each month by another matrix C, then

C = $\left[\begin{array}{cccc}T&H&S&P\\S&500&1400&1400\\L&500&500&500\end{array}\right]$ .

This restocking will be done for 5 times before the end of June.

If there would be no sale, then the stock would be

B + 5C = $\left[\begin{array}{cccc}T&H&S&P\\S&1000+2500&3000+7000&6000+7000\\L&1000+2500&6000+2500&3000+2500\end{array}\right] \\= \left[\begin{array}{cccc}T&H&S&P\\S&3500&10000&13000\\L&3500&8500&5500\end{array}\right]$ .

Since, the total sale is given by 6A, at the end of June, the inventory in each store can be shown as following,

B+5C-6A $\left[\begin{array}{cccc}T&H&S&P\\S&3500&10000&13000\\L&3500&8500&5500\end{array}\right] - \left[\begin{array}{cccc}T&H&S&P\\S&3600&7800&12000\\L&2400&1800&2400\end{array}\right] \\= \left[\begin{array}{cccc}T&H&S&P\\S&-100&2200&1000\\L&1100&6700&3100\end{array}\right]$

6 0

3 years ago