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tresset_1 [31]
3 years ago
10

Remove parameter y=bsintheta x=bsectheta

Mathematics
1 answer:
lesya [120]3 years ago
8 0
\bf \begin{cases}
y=bsin(\theta)\\\\
x=bsec(\theta)\implies \frac{x}{sec(\theta)}=\boxed{b}\\
----------\\
y=\boxed{\frac{x}{sec(\theta)}}sin(\theta)
\end{cases}
\\\\\\
\textit{and you can simplify it further if you want}
\\\\\\

y=\cfrac{xsin(\theta)}{\frac{1}{cos(\theta)}}\implies y=\cfrac{xsin(\theta)}{1}\cdot \cfrac{cos(\theta)}{1}\implies y=xsin(\theta)cos(\theta)
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Identify an equation in slope-intercept from for the line parallel to y=-3x + 7 that passes through (2, -4)
alexandr1967 [171]

The slope-intercept form:

y = mx + b

m - slope

b - y-intercept

The parallel lines have the same slope.

We have y = -3x + 7 → m = -3. Therefore y = -3x + b.

Put the coordinates of the point (2, -4) to the equation of a line:

-4=-3(2)+b

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7 0
2 years ago
Is the relationship shown by the data linear? If so, model the data with an equation.
zhenek [66]

Answer:

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Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( -7, 5 )  

point B( x₂ , y₂) ≡ (-5, 9)  

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Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula

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3 years ago
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:)
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3 years ago
Read 2 more answers
I don’t get the second question.
tatyana61 [14]

it should be 3+(-7)  because look at the number closest to the number line, which is positive 3 then the number next to it is negative 7 because it is heading downward towards the opposing side.  

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