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3 years ago

Remove parameter y=bsintheta x=bsectheta

1 answer:

8 0

$\bf \begin{cases}
y=bsin(\theta)\\\\
x=bsec(\theta)\implies \frac{x}{sec(\theta)}=\boxed{b}\\
----------\\
y=\boxed{\frac{x}{sec(\theta)}}sin(\theta)
\end{cases}
\\\\\\
\textit{and you can simplify it further if you want}
\\\\\\

y=\cfrac{xsin(\theta)}{\frac{1}{cos(\theta)}}\implies y=\cfrac{xsin(\theta)}{1}\cdot \cfrac{cos(\theta)}{1}\implies y=xsin(\theta)cos(\theta)$

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STatiana [176]

Answer:

more than 7

Step-by-step explanation:

4+3 = 7

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3 years ago

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Ronch [10]

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3 years ago

Work out the gradient of the line joining the points (2, 3) and (5,7)

Debora [2.8K]

Answer:

The gradient of the line joining the points $P(x,y) = (2,3)$ and $Q(x,y) = (5,7)$ is $\frac{4}{3}$ .

Step-by-step explanation:

The gradient of the line joining two distinct point on a plane is represented by the slope of a secant line ( $m_{PQ}$ ), that is:

$m_{PQ} = \frac{y_{Q}-y_{P}}{x_{Q}-x_{P}}$ (1)

If we know that $P(x,y) = (2,3)$ and $Q(x,y) = (5,7)$ , then the gradient of the line is:

$m_{PQ} = \frac{7-3}{5-2}$

$m_{PQ} = \frac{4}{3}$

The gradient of the line joining the points $P(x,y) = (2,3)$ and $Q(x,y) = (5,7)$ is $\frac{4}{3}$ .

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3 years ago

Quadrilateral ABCD is similar to quadrilateral EFGH the length of the three longest side in quadrilateral ABCD are 24 feet 16 fe

Triss [41]

Check the picture below

solve for "x"

since we know the two smallest sides for EFGH are 9 and 18, 9 is the smallest of all, and 18 is the next small

thus, for the the quadrilateral ABCD, the smallest is "x" and the next small is given, is 12, since that's smaller than 16 or 24

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3 years ago

A line passes through (−1, 7) and (2, 10).

Pachacha [2.7K]

The slope m of a line through points $A(x_1, y_1)$ and $B(x_2, y_2)$ is given by :

$\displaystyle{m = \frac{y_2-y_1}{x_2-x_1}
$

Thus, the slope of the line passing through points (−1, 7) and (2, 10) is

 $\displaystyle{m= \frac{10-7}{2-(-1)}= \frac{3}{3}=1$


The equation of a line with slope m passing through a point P(a, b) is given by
(y-b)=m(x-a).

We can consider any of the points (-1, 7), or (2, 10). Let's choose (2, 10):

y-10=1(x-2)
y-10=x-2
y-x=-2+10
y-x=8

Answer: C. −x+y=8

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3 years ago