Remove parameter y=bsintheta x=bsectheta

1 answer:

8 0

$\bf \begin{cases}
y=bsin(\theta)\\\\
x=bsec(\theta)\implies \frac{x}{sec(\theta)}=\boxed{b}\\
----------\\
y=\boxed{\frac{x}{sec(\theta)}}sin(\theta)
\end{cases}
\\\\\\
\textit{and you can simplify it further if you want}
\\\\\\

y=\cfrac{xsin(\theta)}{\frac{1}{cos(\theta)}}\implies y=\cfrac{xsin(\theta)}{1}\cdot \cfrac{cos(\theta)}{1}\implies y=xsin(\theta)cos(\theta)$

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