Answer:
19.3 g/mL
Explanation:
The following data were obtained from the question:
Mass (m) = 12.4 kg
Volume (V) = 642 mL.
Density (D) =.?
Next, we shall convert 12.4 kg to grams. This can be obtained as follow:
1 kg = 1000 g
Therefore,
12.4 kg = 12.4 × 1000
12.4 kg = 12400 g
Therefore, 12.4 kg is equivalent to 12400 g.
Finally, we shall determine the density of the gold as follow:
Density is simply defined as the mass of the substance per unit volume of the substance. It can be represented mathematically as:
Density (D) = mass (m) / volume (V)
D = m/V
With the above formula, the density of gold can easily be obtained as follow:
Mass (m) = 12400 g
Volume (V) = 642 mL.
Density (D) =.?
D = m/V
D = 12400/642
D = 19.3 g/mL
Therefore, the density of hold is 19.3 g/mL
<span>First we need to find the energy of one photon with a wavelength of 589 nm.
E = hc / wavelength
E = (6.63 x 10^{-34} J s)(3 x 10^8 m/s) / (589 x 10^{-9} m)
E = 3.3769 x 10^{-19} Joules
To find N, the number of photons, we need to divide the total energy by the energy of each photon.
N = 623000 J / 3.3769 x 10^{-19} Joules
N = 1.84 x 10^{24} photons
There are 1.84 x 10^{24} photons in the burst of yellow light.</span>
Explanation:
Relation between pressure of water and its droplet is as follows.
where, p = pressure of droplet
= water pressure in given temperature
=
M = Molecular Weight in Kg/Mol (0.018 for water)
r = radius in meters
= density of water in
(1000
)
R = ideal gas constant (8.31)
T = temperature in Kelvin
(a)
We will calculate the value of p as follows.
p =
=
= 26.8 torr
(b) And, vapor pressure of spherical water droplets of radius 2.0
or 
p =
=
= 25.2 torr
Answer:
A. All sites B. A site C. E site D. P site
Explanation:
A. Because all sites consequently take place while peptide is synthesized.
B. A site (aminoacyl site) is called so because it binds to charged aminoacyl peptide.
C. Because it is the exit site and it takes the final stage on the uncharged molecule.
D. The P site (peptidil site which takes main role in peptide synthesis.